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arlik [135]
2 years ago
7

If ln(4x+y)=2x-3,then dy/dx=

Mathematics
1 answer:
Viktor [21]2 years ago
4 0

\ln(4x+y)=2x-3

Differentiate both sides wrt x:

\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}

By the chain rule, we get

\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2

\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2

Solve for \frac{\mathrm dy}{\mathrm dx}:

4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y

\boxed{\dfrac{\mathrm dy}{\mathrm dx}=8x+2y-4}

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sergeinik [125]
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Answer:

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Ainat [17]

Answer:

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