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mrs_skeptik [129]
3 years ago
11

When the park opened for the day, four people were in attendance. Every hour, the number of people tripled from the previous hou

r's attendance.
Part A: Determine the common ratio between the attendance each hour.

Part B: Write an equation that can be used to determine the attendance for the nth hour the park is open.

Part C: How many people were at the park during the second, fifth, and eighth hours the park was open? Show all work.
Mathematics
1 answer:
djyliett [7]3 years ago
5 0
This will be Part:C if you need step
By step just reply but hope this helps !
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A train is traveling at 60 mph. If the rate of speed increases 4 mph each hour,
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Answer:

B) 5 hours

Step-by-step explanation:

First, find the amount of mph between 60 and 80:

80 - 60

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Since the speed increases 4 mph per hour, we can find how long it will take to get to 80 mph by dividing 20 by 4:

20/4

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So, the correct answer is B, 5 hours

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2 years ago
What's the fraction root of 9 over 49?
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<span>√9/49

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5 0
3 years ago
Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which
alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L

1.25 liters of oil are needed.

6 0
3 years ago
The population of a city on April 15, 1915, was 47,175. During the period between March 1 and July 1, 1915, 1,325 new cases of s
Norma-Jean [14]

Answer:

the incidence rate is 28.47

Step-by-step explanation:

The computation of the monthly incident rate of active cases is shown below:

Incidence rate is

= 1325 ÷  (47175 - 642) × 1000

= (1325 ÷ 46533 ) ×  1000

= 28.47

hence, the incidence rate is 28.47

7 0
3 years ago
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