Answer:
, ](https://tex.z-dn.net/?f=%5B16%20%2B%20%28-18%29%5D%28-4%29)
Step-by-step explanation:
Given: The low temperature on Monday was 16°F. The low temperature on Tuesday was 18°F cooler. The low temperature on Wednesday was –4 times Tuesday’s temperature.
To find: expression that can be used to describe the low temperature on Wednesday
Solution:
Temperature on Monday = 16°F
So,
Temperature on Tuesday = 
Temperature on Wednesday = 
So, expression 
can be used to describe the low temperature on Wednesday.
Also,
\,\,\left \{\because (a-b)=\left [ a+(-b) \right ] \right \}](https://tex.z-dn.net/?f=%2816-18%29%28-4%29%3D%5B16%20%2B%20%28-18%29%5D%28-4%29%5C%2C%5C%2C%5Cleft%20%5C%7B%5Cbecause%20%20%28a-b%29%3D%5Cleft%20%5B%20a%2B%28-b%29%20%5Cright%20%5D%20%5Cright%20%5C%7D)
So, expression also represent temperature on Wednesday.
Answer:
The anser is 5 hop this helps sorry if it is wrong
Step-by-step explanation:
Answer: 46.90mins
Step-by-step explanation:
The given data:
The diameter of the balloon = 55 feet
The rate of increase of the radius of the balloon when inflated = 1.5 feet/min.
Solution:
dr/dt = 1.5 feet per minute = 1.5 ft/min
V = 4/3·π·r³
The maximum volume of the balloon
= 4/3 × 3.14 × 55³
= 696556.67 ft³
When the volume 2/3 the maximum volume
= 2/3 × 696556.67 ft³
= 464371.11 ft³
The radius, r₂ at the point is
= 4/3·π·r₂³
= 464371.11 ft³
r₂³ = 464371.11 ft³ × 3/4
= 348278.33 ft³
348278.333333
r₂ = ∛(348278.33 ft³) ≈ 70.36 ft
The time for the radius to increase to the above length = Length/(Rate of increase of length of the radius)
The time for the radius to increase to the
above length
Time taken for the radius to increase the length.
= is 70.369 ft/(1.5 ft/min)
= 46.90 minutes
46.90mins is the time taken to inflate the balloon.
Answer:
8n+5=6
Step-by-step explanation:
Answer:
-5
Step-by-step explanation:
