AgC2H3O2 + K2CrO4 = Ag2CrO4 + KC2H3O2 How many moles of silver chromate, Ag2CrO4 are produced in this reaction

Chemistry

1 answer:

Tom [10]3 years ago

4 0

Taking into account the reaction stoichiometry, 1 mole of silver chromate Ag₂CrO₄ are produced in this reaction.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgC₂H₃O₂ + K₂CrO₄ → Ag₂CrO₄ + 2 KC₂H₃O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

AgC₂H₃O₂: 2 moles
K₂CrO₄: 1 mole
Ag₂CrO₄: 1 mole
KC₂H₃O₂: 2 moles

<h3>Moles of Ag₂CrO₄ formed</h3>

By reaction stoichiometry 2 moles of AgC₂H₃O₂ form 1 mole of Ag₂CrO₄.

In other words, according to this balanced chemical equation, 1 mole of silver chromate Ag₂CrO₄ are produced in this reaction.

Learn more about the reaction stoichiometry:

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