Information gathered by a scientist abut the toxicity of chemical X and chemical Y showed that they had individual safe limits f
1 answer:
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Answer:
The specific heat capacity of the unknown metal is 0.223
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
- Q= 418.6 J
- c= ?
- m= 75 g
- ΔT= 25 C
Replacing:
418.6 J= c* 75 g* 25 C
Solving:
c= 0.223
<u><em>The specific heat capacity of the unknown metal is 0.223 </em></u><u><em></em></u>
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We know that the equation for density is:
where D is the density, m is the mass in grams, and V is the volume.
Given two of the variables, we can then solve for density:
So therefore, we now know that the density of carbon dioxide gas is 0.00196g/mL.
Answer:
0.56L
Explanation:
This question requires the Ideal Gas Law: where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.
Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units:
Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means and
Lastly, we must calculate the number of moles of there are. Given 0.80g of
, we will need to convert with the molar mass of
. Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2:
Thus,
Isolating V in the Ideal Gas Law:
...substituting the known values, and simplifying...
So, 0.80g of would occupy 0.56L at STP.