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Inga [223]
2 years ago
15

Is it possible for cells to overcome the effects of alkylating agents? how?

Chemistry
1 answer:
koban [17]2 years ago
8 0
Selected Alkylating Agents Can Overcome Drug Tolerance of G 0-like Tumor Cells and Eradicate BRCA1-Deficient Mammary Tumors in Mice. Clin Cancer Res
You might be interested in
Using the van der Waals equation, the pressure in a 22.4 L vessel containing 1.00 mol of neon gas at 100 °C is ________ atm. (a
svetoff [14.1K]

Answer:

The answer to your question is        P = 1.357 atm

Explanation:

Data

Volume = 22.4 L

1 mol

temperature = 100°C

a = 0.211 L² atm

b = 0.0171 L/mol

R = 0.082 atmL/mol°K

Convert temperature to °K

Temperature = 100 + 273

                      = 373°K

Formula

               (P + \frac{a}{v^{2}} )(v - b) = RT

Substitution

               (P + \frac{0.211}{22.4})(22.4 - 0.0171) = (0.082)(373)

Simplify

               (P + 0.0094)(22.3829) = 30.586

Solve for P

                           P + 0.0094 = \frac{30.586}{22.3829}

                           P + 0.0094 = 1.366

                                 P = 1.336 - 0.0094

                                P = 1.357 atm

7 0
3 years ago
Define the term standardization
trapecia [35]

Explanation:

Standardization is the process of creating protocols to guide the creation of a good or service based on the consensus of all the relevant parties in the industry. ... Standardization also helps in ensuring the safety, interoperability, and compatibility of goods produced.

6 0
2 years ago
56. The electron configuration for phosphorous is [Ar]3s23p4.<br> a. TRUE<br> b. FALSE
melomori [17]

Answer:

False

Explanation:

7 0
2 years ago
Read 2 more answers
Calculate the number of moles of iodine in 7.68×10^25 molecules of I2
Dmitrij [34]

Answer:

<h2>127.57 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.68 \times  {10}^{25} }{6.02 \times  {10}^{23} }   \\  = 127.574750...

We have the final answer as

<h3>127.57 moles</h3>

Hope this helps you

4 0
2 years ago
Please help with number 24
vladimir1956 [14]
Layla it is A. that's the only one in standard form.
3 0
3 years ago
Read 2 more answers
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