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2 years ago

Is it possible for cells to overcome the effects of alkylating agents? how?

1 answer:

8 0

Selected Alkylating Agents Can Overcome Drug Tolerance of G 0-like Tumor Cells and Eradicate BRCA1-Deficient Mammary Tumors in Mice. Clin Cancer Res

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All elements are pure substances.<br><br> True<br><br> False

oee [108]

It can be a compound or a single element. An element is a pure substance that cannot be separated into simpler substances by chemical or physical means. There are about 117 elements, but carbon, hydrogen, nitrogen and oxygen are only a few that make up the largest portion of Earth.
hopefully that helps

5 0

3 years ago

Tuliskan persamaan tetapan kesetimbangan untuk reaksi-reaksi berikut a. Fe3+(aq) + SCN– (aq) ↔ FeSCN3+(aq) b. 3Fe(s) + 4H2O(g) ↔

nevsk [136]

Answer:

a. $K_c = \dfrac{[ FeSCN^{3+}_{(aq)}] }{[Fe^{3+}_{(aq)}] [SCN^-_{(aq)}]}$

b. $K_p = \dfrac{[H_2]^4}{[H_2O]^4}$

Explanation:

Untuk semua jenis reaksi umum:

$aA + bB\iff cC + dD$

Konstanta kesetimbangan $K_c = \dfrac{[C]^c [D]^d}{[A]^a[B]^b}$

Dari pertanyaan yang diberikan:

a. $Fe3^+_{(aq)} + SCN^-_{ (aq)} \iff FeSCN^{3+}_{(aq) }$

Konstanta kesetimbangan:

$K_c = \dfrac{[ FeSCN^{3+}_{(aq)}] }{[Fe^{3+}_{(aq)}] [SCN^-_{(aq)}]}$

b. $3Fe_{(s)} + 4H_2O_{(g)} \iff Fe_3O_4_{(s)} + 4H_{2(g)}$

Konstanta kesetimbangan untuk tekanan parsial $K_p$

$K_p = \dfrac{[H_2]^4}{[H_2O]^4}$

Karena Fe3O4 (s) hadir sebagai padatan.

8 0

2 years ago

The decomposition of NH4HS is endothermic: NH4HS(s)⇌NH3(g)+H2S(g) Part A Which change to an equilibrium mixture of this reaction

shepuryov [24]

Explanation:

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

As the given reaction is as follows.

$NH_{4}HS(s) \rightleftharpoons NH_{3}(g) + H_{2}S(g)$

(a) When increase the temperature of the reactants or system then equilibrium will shift in forward direction where there is less temperature. It is possible for an endothermic reaction.

Thus, formation of $H_{2}S$ will increase.

(b) When we decrease the volume (at constant temperature) of given reaction mixture then it implies that there will be increase in pressure of the system. So, equilibrium will shift in a direction where there will be decrease in composition of gaseous phase. That is, in the backward direction reaction will shift.

Hence, formation of $H_{2}S$ will decrease with decrease in volume.

When we increase the mount of $NH_{4}HS$ then equilibrium will shift in the direction of decrease in concentration that is, in the forward direction.

Thus, we can conclude that formation of $H_{2}S$ will increase then.

3 0

3 years ago

If more solute can be dissolved in a solvent, the solution is

Mekhanik [1.2K]

Answer: B. Unsaturated

Explanation: in a saturated/super saturated solution, more solute will not be able to dissolve.

8 0

3 years ago

What is chemistry? I NEED HELP ASAP!

Thepotemich [5.8K]

the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.

3 0

2 years ago