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Tems11 [23]
3 years ago
7

A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calc

ulate the specific heat of aluminum.
Chemistry
2 answers:
ivann1987 [24]3 years ago
7 0

Answer:

Explanation:

Specific heat is defined as the amount of energy required to heat or cool 1 kg of a substance by 1°C.

It is given:

energy is 1080 joules,

mass is 140g; i.e. 0.14kg,

temperature change is 98.4 - 62.2 = 36.2°C

So the specific heat of aluminum = 1080 / 0.14 / 36.2

= 213.1 J/kg/°C

GrogVix [38]3 years ago
3 0

<u>Answer:</u>

Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.

Unit is <em>(\frac {J}{Kg.K})</em>

<em>C = Q/m. ∆T</em>

<em>C – Specific heat (\frac {J}{Kg.K})</em>

<em>Q- heat energy (J)</em>

<em>M – Mass (Kg)</em>

<em>∆T- change in temperature (K) </em>

<u>Explanation:</u>

<em>Given data:</em>

<em>M= 140 g = 0.14 Kg</em>

<em>Q – 1080 Joules.</em>

<em>∆T – 98.4 – 62.2 = 36.2</em>

Substituting  the given data in Equation

<em>Specific heat of Aluminium  = \frac {1080}{(0.14 \times 36.2)} = 213.10 (\frac {J}{Kg.K})</em>

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