You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
Answer:
m=2/3
Step-by-step explanation:
your answer would be A.
I am sorry i don’t understand can you just type it again ?
Answer:
fourth picture
Step-by-step explanation:
4x - 2 > 6
4x > 8
x > 2
x + 3 <= -6
x <= -9
so answer in interval notation is (-∞, -9] or (2, ∞)
