Step-by-step explanation:
t1 = 1 = 7*1 - 6
t2 = 8 = 7* 2 - 6
t3 = 15 = 7 * 3 - 6
t4 = 22 = 7 *4 - 6
t5 = 29 = 7 * 5 - 6
-------------------------
Tn = 7n - 6
Answer: Option C - Construction Y because point E is the circumcentre of triangle LMN.
Point E is the best location for the warehouse as it is exactly equidistant from the three stores at L, M and N.
Step-by-step explanation:
Before solving an algebra problem, it sometimes helps to get a geometric picture of what's happening. Geometry says that three points determine a circle - in other words, given three points that are not
all on the same line, there is exactly one circle which passes through all 3. Finding the point equidistant from the 3 points is the same thing as finding the center of the circle that passes through all of them (since all points on a circle are equidistant from the center).
Our points are L, M and N. Draw the lines LM, LN and MN to form a triangle. Now construct the perpendicular bisectors of any two of the lines, and their intersection, point E, will be the center of this circle.
As shown in the Construction Y because E is the circumcentre of triangle LMN.
This is the best location for the warehouse as it is exactly equidistant from the three stores at L, M and N.
QED!
Answer:
Parallel line:

Perpendicular line:

Step-by-step explanation:
we are given equation 4x+5y=19
Firstly, we will solve for y

we can change it into y=mx+b form


so,

Parallel line:
we know that slope of two parallel lines are always same
so,

Let's assume parallel line passes through (1,1)
now, we can find equation of line

we can plug values

now, we can solve for y

Perpendicular line:
we know that slope of perpendicular line is -1/m
so, we get slope as

Let's assume perpendicular line passes through (2,2)
now, we can find equation of line

we can plug values

now, we can solve for y

Answer:
The width of the drawer is 
Step-by-step explanation:
we know that
The volume of the drawer is equal to

we have

-----> the deep of the drawer

substitute the given values in the formula and solve for W



