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choli [55]
3 years ago
11

-4x+y=3 and 2x-y=12. which of the options represents the resulting equation after an equivalent expression for yw is substituted

into the second equation. Odessyware!
Mathematics
1 answer:
forsale [732]3 years ago
4 0

Answer:

2x - (3 + 4x) = 12

x = -7.5

y = -27

Step-by-step explanation:

-4x + y = 3 (1)

2x - y = 12 (2)

From (1)

y = 3 + 4x

Substitute y = 3 + 4x into (2)

2x - y = 12 (2)

2x - (3 + 4x) = 12

2x - 3 - 4x = 12

2x - 4x = 12 + 3

-2x = 15

x = 15/-2

x = -7.5

Substitute x = -7.5 into (2)

2x - y = 12 (2)

2(-7.5) - y = 12

-15 - y = 12

-y = 12 + 15

- y = 27

y = -27

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Two trains travel at right angles to each other after leaving the same train station at the same time. Two hours later they are
Alex787 [66]

Answer:

15 miles per hour is the speed of the slower train.

Step-by-step explanation:

As given in the figure attached,

Let the speed of train 1 is v and train 2 is u.

Therefore, distance traveled in 2 hours by train 1 will be = 2v miles

and distance traveled by train 2 will be = 2u miles

Now we can see in the figure a right angle triangle is formed by the two trains.

AB² + BC² = AC²

(2v)² + (2u)²= (65.30)²

4v² + 4u² = 4264.09

Now we divide this equation by 4

v² + u² = 1066.02

If speed of the slower train is v miles per hour then as per statement of the question.

u = v - 14

v = u + 14

By putting the value of v in the equation

(u + 14)² + u² = 1066

u² + 196 + 28u + u² = 1066

2u² + 28u + 196 = 1066

2u² + 28u + 196 - 1066 = 0

2u² + 28u - 870 = 0

By diving this equation by 2

u² + 14u - 435 = 0

u² + 29u - 15u - 435 = 0

u(u + 29) - 15(u + 29) = 0

(u + 29)(u - 15) = 0

u = -29, 15

Since speed can not be with negative notation so u = 15 miles per hour will be the speed.

Therefore, 15 miles per hour is the speed of the slower train.

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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distribute the 2

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add/ subtract like terms

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