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Semmy [17]
2 years ago
10

Factor completely 8y²+6y+1​

Mathematics
2 answers:
mel-nik [20]2 years ago
7 0
(2y +1)(4y + 1) is the factored form
jeka942 years ago
5 0

(4y + 1)(2y +1) this should be the answer: How to solve your problem
8

2
+
6

+
1
8
y
2
+
6
y
+
1
Grouping
1
Use the sum-product pattern
8

2
+
6

+
1
8
y
2
+
6
y
+
1
8

2
+
4

+
2

+
1
8
y
2
+
4
y
+
2
y
+
1
2
Common factor from the two pairs
8

2
+
4

+
2

+
1
8
y
2
+
4
y
+
2
y
+
1
4

(
2

+
1
)
+
2

+
1
4
y
(
2
y
+
1
)
+
2
y
+
1
3
Rewrite in factored form
4

(
2

+
1
)
+
2

+
1
4
y
(
2
y
+
1
)
+
2
y
+
1
(
4

+
1
)
(
2

+
1
)
(
4
y
+
1
)
(
2
y
+
1
)
Solution
(
4

+
1
)
(
2

+
1
)

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strojnjashka [21]

Answer:

₹42,500

Step-by-step explanation:

Let Sonali's monthly income be ₹x

<h2>According to the question </h2>

15\% \:ofx + 55\% \: of \: x + 12750 = x

=  >  \frac{15}{100} x +  \frac{55}{100} x + 12750 = x

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