Factor completely 8y²+6y+1
2 answers:
(2y +1)(4y + 1) is the factored form
(4y + 1)(2y +1) this should be the answer: How to solve your problem
8
2
+
6
+
1
8
y
2
+
6
y
+
1
Grouping
1
Use the sum-product pattern
8
2
+
6
+
1
8
y
2
+
6
y
+
1
8
2
+
4
+
2
+
1
8
y
2
+
4
y
+
2
y
+
1
2
Common factor from the two pairs
8
2
+
4
+
2
+
1
8
y
2
+
4
y
+
2
y
+
1
4
(
2
+
1
)
+
2
+
1
4
y
(
2
y
+
1
)
+
2
y
+
1
3
Rewrite in factored form
4
(
2
+
1
)
+
2
+
1
4
y
(
2
y
+
1
)
+
2
y
+
1
(
4
+
1
)
(
2
+
1
)
(
4
y
+
1
)
(
2
y
+
1
)
Solution
(
4
+
1
)
(
2
+
1
)
You might be interested in
Answer:
19460
Step-by-step explanation:
5 times 28= 140
140 squared =( 140 times 140)=19600
19600 - 5 times 28
19600 - 140= 19460
Answer:
50.4
Step-by-step explanation:
6x -3 + 4x = 5 + 3x + 4
10 -3 = 3x + 9
answer is C.
Answer:
growth because 'b' > 1 b decay because 'b' is < 1
It helps to use your factor pairs
