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3 years ago

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Which shows the mean, median, mode, and range for this set of data?

1 answer:

Brums [2.3K]3 years ago

6 0

8.3,4.5,6.2,9.6,4.3,11.2,5.9,9.7,10.5

Mean:
To find mean you do the same as you would to find an average. Add up all of the numbers and divide by how many numbers are there. So,
8.3 + 4.5 + 6.2 + 9.6 + 4.3 + 11.2 + 5.9 + 9.7 + 10.5 = 70.2
Then divide by 9 since you have 9 numbers.
70.2 / 9 = 7.8

Median:
To find median you set up the data from least to greatest and cross out one number from each side until you are left with one number as the middle number.
4.3, 4.5, 5.9, 6.2, 8.3, 9.6, 9.7, 10.5, 11.2
4.5, 5.9, 6.2, 8.3, 9.6, 9.7, 10.5
5.9, 6.2, 8.3, 9.6, 9.7
6.2, 8.3, 9.6
= 8.3
Mode:
Mode is the most, meaning the number that appears the most in your set of data. In this case there is no mode because in your set there is no number that occurs more than once.

Hope this helps!

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A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

Studentka2010 [4]

Using the z-distribution, it is found that the needed sample sizes are:

a) 242

b) 1842

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99% confidence level, hence $\alpha = 0.99$ , z is the value of Z that has a p-value of $\frac{1+0.99}{2} = 0.995$ , so $z = 2.575$ .

Item a:

The estimate is:

$\pi = 0.223 - 0.189 = 0.034$

The sample size is <u>n for which M = 0.03</u>, then:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 2.575\sqrt{\frac{0.034(0.966)}{n}}$

$0.03\sqrt{n} = 2.575\sqrt{0.034(0.966)}$

$\sqrt{n} = \frac{2.575\sqrt{0.034(0.966)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{2.575\sqrt{0.034(0.966)}}{0.03}\right)^2$

$n = 241.97$

Rounding up, a sample of 242 is needed.

Item b:

No prior estimates, hence $\pi = 0.5$ is used.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 2.575\sqrt{\frac{0.5(0.5)}{n}}$

$0.03\sqrt{n} = 2.575\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{2.575\sqrt{0.5(0.5)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{2.575\sqrt{0.5(0.5)}}{0.03}\right)^2$

$n = 1841.8$

Rounding up, a sample of 1842 is needed.

For more on the z-distribution, you can check brainly.com/question/25404151

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ikadub [295]

Answer:

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Step-by-step explanation:

Since $15,000 is over $5000 the commission is 7.5%

Next you turn the percent into a decimal:

0.075

Now multiply $15,000 by 0.075

Answer = $1125

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Answer:

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1/12

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Ahat [919]

Answer:

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Step-by-step explanation:

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