Which shows the mean, median, mode, and range for this set of data?

1 answer:

6 0

8.3,4.5,6.2,9.6,4.3,11.2,5.9,9.7,10.5

Mean:
To find mean you do the same as you would to find an average. Add up all of the numbers and divide by how many numbers are there. So,
8.3 + 4.5 + 6.2 + 9.6 + 4.3 + 11.2 + 5.9 + 9.7 + 10.5 = 70.2
Then divide by 9 since you have 9 numbers.
70.2 / 9 = 7.8

Median:
To find median you set up the data from least to greatest and cross out one number from each side until you are left with one number as the middle number.
4.3, 4.5, 5.9, 6.2, 8.3, 9.6, 9.7, 10.5, 11.2
4.5, 5.9, 6.2, 8.3, 9.6, 9.7, 10.5
5.9, 6.2, 8.3, 9.6, 9.7
6.2, 8.3, 9.6
= 8.3
Mode:
Mode is the most, meaning the number that appears the most in your set of data. In this case there is no mode because in your set there is no number that occurs more than once.

Hope this helps!

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So.. if you take a peek at the picture below

the trunk is really just a half-cylinder on top of a square, with a depth of 2 meters

what's the volume? well, easy enough, take the volume of the cylinder, then half it
take the volume of the rectangular prism, and then add them both

$\bf \textit{volume of a cylinder}\\\\

\begin{array}{llll}
C=\pi r^2 h\\\\
\textit{half that}\\\\
\cfrac{\pi r^2 h}{2}
\end{array}\qquad 
\begin{cases}
r=radius\\
h=height\\
-------\\
r=\frac{1}{2}\\
h=2
\end{cases}\implies \cfrac{C}{2}=\cfrac{\pi \left( \frac{1}{2}\right)^2 2}{2}\\\\
-----------------------------\\\\
\textit{volume of a square}\\\\
V=lwh\qquad 
\begin{cases}
l=length\\
w=width\\
h=height
----------\\
l=1\\
w=1\\
h=2
\end{cases}\implies V=2$

now.. for the surface area... $\bf \textit{surface area of a cylinder}\\\\
\begin{array}{llll}
S=2\pi r(h+r)\\\\
\textit{half that}\\\\
\cfrac{2\pi r(h+r)}{2}
\end{array}\begin{cases}
r=radius\\
h=height\\
-------\\
r=\frac{1}{2}\\
h=2
\end{cases}$

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is really just 6 rectangles stacked up to each other at the edges

so... get the area of the lateral rectangles, and the one at the bottom, skip the rectangle atop, because is the one overlapping the cylinder, and is not outside, and thus is not surface area then

for the lateral ones, you have a front of 1x1, a back of 1x1 and a left of 1x2 and a right of 1x2, and then the one at the bottom, which is a 1x2

then add both surface areas, and that's the surface area of the trunk