One number that is divisible by both 3 and 4 is 12. Any multiple of 12 is also divisible by both 3 and 4, such as 24, 36, 48, etc.
-99..?? I think that’s the answer
Answer:
1.67 this is rounded but original is just endless 6
Step-by-step explanation:
1 6/9
1 2/3
1.66
Hopes this help please mark brainliest
To solve a problem like this, we need to start with the innermost parenthesis. Doing that, we get to 4+1, evaluating it giving us 5. This turns our expression into 5 x {3 x [9 - 5]} + 20 ÷ 4 x 2.
Now, the innermost parenthesis is 9-5. Evaluating that gives us 4. Our expression is now 5 x {3 x 4} + 20 ÷ 4 x 2.
Once again, we go to the innermost parenthesis and evaluate whatever is there. This turns our expression into <span>5 x 12 + 20 ÷ 4 x 2.
Now, we can simply use order of operations to compute that the value of the expression is equal to 70. </span>
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
