Answer:
2 Times
Step-by-step explanation:
Simon can see two lights A and B
- Light A flashes every 15 seconds.
- Light B flashes every 18 seconds.
First, we determine the next time both lights will flash together.
This is done by finding the Least Common Multiple of 15 and 18.
15=3X5
18=
LCM of 15 and 18=
This means that lights A and B will first flash together after 90 seconds.
Now, 240/90=
seconds
Therefore, the number of times more both light will flash together in the next 4 Minutes= 2 Times
Answer:
d
Step-by-step explanation:
Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
