Half of number q is 4

scoray [572]

Answer:

(10,6)

Step-by-step explanation:

The equation you would use to solve this is (x1+x2/2 , y1+y2/2) so when you plug in the numbers you get this (6+14/2 , 3+9/2) which eventually simplifies into (10, 6)

3 0

3 years ago

Se quiere construir un muro de 4 m de alto, 12 m de largo y 10 cm de espesor. ¿Cuántos ladrillos de 8 cm de alto, 20 cm de largo

Llana [10]

Answer:

3000

Step-by-step explanation:

Let's start by finding the volume of the wall. The volumen of the wall can be considered as the volume of a rectangular prism. The volume of a rectangular prism is given by:

$V_w=w*l*h\\\\Where:\\\\w=Width=10cm=0.1m\\l=Length=12m\\h=Height=4m$

So the volume of the wall is:

$V_w=0.1*12*4=4.8m^3$

Now, we can find the volume of the brick using the same method since a brick can be considered as a rectangular prism as well:

$V_b=w*l*h\\\\For\hspace{3}the\hspace{3}brick\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m$

Hence:

$V_b=(0.1)*(0.2)*(0.08)=0.0016m^3$

In order to know how many bricks are required to build the wall, we just need to fill the wall volume with the number of bricks of this volume. So:

$V_w=nV_b\\\\Where\\\\n=Number\hspace{3}of\hspace{3}bricks$

Solving for n:

$n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000$

Therefore, we need 3000 bricks to build that wall.

Translation:

Comencemos por encontrar el volumen del muro. El volumen del muro puede considerarse como el volumen de un prisma rectangular. El volumen de un prisma rectangular viene dado por:

$V_w=w*l*h\\\\Donde:\\\\w=Espesor=10cm=0.1m\\l=Largo=12m\\h=Alto=4m$

Entonces el volumen del muro es:

$V_w=0.1*12*4=4.8m^3$

Ahora, podemos encontrar el volumen del ladrillo utilizando el mismo método, ya que un ladrillo también puede considerarse como un prisma rectangular:

$V_b=w*l*h\\\\Para\hspace{3}el\hspace{3}ladrillo\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m$

Por lo tanto:

$V_b=(0.1)*(0.2)*(0.08)=0.0016m^3$

Para saber cuántos ladrillos se requieren para construir el muro, solo necesitamos llenar el volumen del muro con la cantidad de ladrillos de este volumen. Entonces:

$V_w=nV_b\\\\Donde\\\\n=Numero\hspace{3}de\hspace{3}ladrillos$

Resolviendo para n:

$n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000$

Por lo tanto, necesitamos 3000 ladrillos para construir ese muro.

4 0

3 years ago

You’d like to see how many baseball and soccer games you can attend this spring. Travel time for basketball games is 2 hours and

Eddi Din [679]

4 basketball games and 7 soccer games

8 0

3 years ago

The charge to rent a movie from a store is $3.50 for 3 days, which includes the day the movie is rented. A late fee of $1.00 is

Dahasolnce [82]

Monday to Friday is 5 days
$3.50 for 3 days + $2.00 for 2 days
=$5.50

7 0

3 years ago

1+2+3+4+5+.........+100= ?<br> The sum of 100 consecutive interger from 1 to 100

Mama L [17]

Answer:

5050

Step-by-step explanation:

Ace here!

So, you could go through and add up everything but that takes a while, and there's a much easier way to do this. Let's write a rough sample of the numbers.

1, 2, 3, 4, 5....96, 97, 98, 99, 100.

Now, let's look at these numbers. Notice how if we add the two numbers on the leftmost and the rightmost, we get 101 (1+100). Now, we do 1 from the left added on to one from the right, and get 101(2+99). Then, we can follow that pattern and do 3+98=101, 4+97=101, and as long as we follow that pattern, we keep getting 101 as our answer.

Now, if we keep going with this, eventually we will get to 48+53, 49+52, 50+51.

If we supposedly counted all these pairs, we would find we have 50 pairs. But a quick way to check is to just divide 100 by 2 (100/2) and we get 50.

Now, we have 50 pairs that add up to 101. So, that would be 101 added to itself 50 times, which is just multiplication. 101 × 50 which is 5050.

I hope this helped. Let me know if you have any questions.

6 0

3 years ago

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