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jenyasd209 [6]
3 years ago
5

Half of number q is 4

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

1/2 (1q) = 4

insert extra text here

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1 3/4 and 1/8 divided as a simplify form
Sati [7]

Simplest form for 1 3/4 would be 7/4

Simplest form for 0.125

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4 years ago
Can someone plz help me
alekssr [168]

Answer:

C = -13.78

Step-by-step explanation:

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3 years ago
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Asap someone help me
Bingel [31]

Answer:

x= 11.4

Step-by-step explanation:

for the base of the triangles BC is 15 and DF is 5 so if 5 times 3 is 15 then you are reducing the other triangle to a third of the big triangles size. so 3.8 times three is 11 4

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3 years ago
Which statement describes the inverse of m(x) = x^2 – 17x?
DochEvi [55]

Given:

The function is

m(x)=x^2-17x

To find:

The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

Substitute m(x)=y.

y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

7 0
3 years ago
(-2,1); perpendicular to y= - 2/5x -4<br><br> Help explain step by step?
Fittoniya [83]

Answer:

  y = (5/2)x + 6

Step-by-step explanation:

The given line has a slope (coefficient of x) of -2/5. The perpendicular line will have a slope that is the negative reciprocal of this:

  -1/(-2/5) = 5/2

Since you are given a point you want the line to go through, the point-slope form of the equation of the line is useful. That form for slope m and point (h, k) is ...

  y = m(x -h) +k

For your slope m=5/2 and point (h, k) = (-2, 1), the equation of the line is ...

  y = 5/2(x +2) +1

  y = 5/2x +6 . . . . . eliminate parentheses

8 0
4 years ago
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