Answer:
We have expanded formula of (-4x-1)² = a²+2ab+b².
So, we write the formula in square form as (a+b)².
Since we have a²-b² in step 4. We further write this as (a+b)(a-b). This is the factor formula of a²-b².
As we had two terms in place of in (a+b)(a-b), we multiply the term 'b' with '+' and '-' sign respectively.
Write the second expression given in the question.
Write the terms in the form of cube.
Write the factor formula of a³-b³) in the form of (a-b)(a²+ab+b²).
Write the H.C.F. (Highest Common Factor) of the given expressions by analysing the factors you generated in each expressions. Here, (4x²+2x+1) are the common factors.
Answer:
A or (2x+1)/(x-1)
Step-by-step explanation:
Let's simplify the top of the fraction first.
1. Simplify the numerator.
2x^2 -7x-4=(2x+1)(x-4)
2. Simplify the denominator.
x^2-5x+4=(x-4)(x-1)
Now we have:
((2x+1)(x-4))/((x-4)(x-1))
We see that there is an (x-4) both on the numerator and denominator.
We can remove (x-4) by division.
Doing that, we have:
(2x+1)/(x-1) or A
