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MakcuM [25]
2 years ago
10

What is the surface area of this triangular pyramid? 3 m 3 m 3 m 3 m 2.6 m​

Mathematics
1 answer:
tekilochka [14]2 years ago
4 0

\stackrel{\textit{3 standing triangles}}{3\left[\cfrac{1}{2}(\stackrel{b}{3})(\stackrel{h}{3}) \right]}~~ + ~~\stackrel{\textit{triangular base}}{\cfrac{1}{2}(3)(2.6)}\implies 13.5~~ + ~~3.9\implies 23.4~m^2

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What is y 12y - 19= 6y+1=
nadezda [96]

Answer:

<h2><u><em>Y= 10/3 or 3.333....</em></u></h2>

Step-by-step explanation:

12y-19= 6y+1

12y-6y = 1 +19

6y = 20

y = 20/6

y= 10/3 or 3.33..

 

<h2><u><em>HAVE A NICE TIME :)</em></u></h2><h2><em>pls give a </em><u><em>brainliest</em></u><em> if it is CORRECT</em></h2>
3 0
2 years ago
A small company had a loss of $425 in January. If it continues to have the same loss each month for 4 months, what will be the c
Tresset [83]
425(4)= 1700. After 4 months they would have lost $1700
3 0
3 years ago
Hoping to attract more shoppers, a city builds a new public parking garage downtown. The city plans to pay for the structure thr
posledela

Answer:

MOE_{95} = 1.192\cdot MOE_{90}

Step-by-step explanation:

The margin of error is computed using the formula:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical of <em>z</em> for 95% confidence level and 90% confidence level are:

z_{0.05/2}=z_{0.025}=1.96\\\\z_{0.10/2}=z_{0.05}=1.645

*Use a <em>z</em>-table.

The sample size is n = 44.

Compare the MOE for 95% confidence level and 90% confidence level as follows:

\frac{MOE_{95}}{MOE_{90}}=\frac{1.96\times (15/\sqrt{44})}{1.645\times (15/\sqrt{44})}

\frac{MOE_{95}}{MOE_{90}}=\frac{1.96}{1.645}\\\\\frac{MOE_{95}}{MOE_{90}}=1.192\\\\MOE_{95} = 1.192\cdot MOE_{90}

6 0
3 years ago
A geometric sequence is defined by the equation an = (3)3 − n.
Delvig [45]
PART A

The geometric sequence is defined by the equation

a_{n}=3^{3-n}

To find the first three terms, we put n=1,2,3

When n=1,

a_{1}=3^{3-1}

a_{1}=3^{2}

a_{1}=9
When n=2,

a_{2}=3^{3-2}
a_{2}=3^{1}

a_{2}=3

When n=3

a_{3}=3^{3-3}

a_{3}=3^{0}
a_{1}=1
The first three terms are,

9,3,1

PART B

The common ratio can be found using any two consecutive terms.

The common ratio is given by,
r= \frac{a_{2}}{a_{1}}
r = \frac{3}{9}

r = \frac{1}{3}

PART C

To find
a_{11}

We substitute n=11 into the equation of the geometric sequence.

a_{11} = {3}^{3 - 11}

This implies that,

a_{11} = {3}^{ - 8}

a_{11} = \frac{1}{ {3}^{8} }

a_{11}=\frac{1}{6561}
4 0
3 years ago
How do I solve this I don't understand?
kykrilka [37]

Answer:

The equation for this sequence will be 8 + 17n - 17 with n being replaced with the term number you are trying to find.

so 8 + 17(16) - 17

17 x 16= 272

8 + 272= 280

280- 17= 263

Thus, the 16th term will be 263.

7 0
3 years ago
Read 2 more answers
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