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2 years ago

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The weights of a certain brand of candies are normally distributed with a mean weight of 0.8593 g and a standard deviation of 0.

0511 g. A sample of these candies came from a package containing 464 candies, and the package label stated that the net weight is 396.1 g. (If every package has 464 candies, the mean weight of the candies must exceed 396.1 464=0.8537 g for the net contents to weigh at least 396.1 g.)

1 answer:

Alex17521 [72]2 years ago

6 0

Answer:

The package label stated that the net weight is 381.8g If every package has ... brand of candies have a mean weight of 0.8616g and a standard deviation of ...

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A construction crew built miles of road in days. What is the unit rate in miles per day? Write your answer as a fraction or a mi

vovikov84 [41]

Complete question :

A construction crew built 1/2 miles of road in 1/8 days. What is the unit rate in miles per day? Write your answer in simplest form.

Answer:

3 miles per day

Step-by-step explanation:

Given that:

1/2 miles of road takes 1/8 days

Unit Rate in miles per day :

Miles of road built / number of days taken

1/2 miles ÷ 1/8 days

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2 years ago

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

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Text per day: median= 26 1st quartile= 19 3rd quartile=38 Interquartile=19 Daily attendance: median=357.5 1st quartile=298 3rd quartile=422 Interquartile= 124

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Answer:

They are Proportional because there will always be a 7 dollar difference

Step-by-step explanation:

Josh is paid 14

Tillery is payed 7$

The relation is proportional

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14 ||| 7

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20 ||| 13

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