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aleksklad [387]
3 years ago
6

The average (arithmetic mean) of a set of n numbers is 19. If the average of the 6 greatest numbers in the set is 29 and the ave

rage of the remaining numbers is 7, what is the value of n?
Mathematics
2 answers:
e-lub [12.9K]3 years ago
4 0

Answer:

  11

Step-by-step explanation:

The number of numbers whose average is 7 is (n-6), so the overall equation for the average of the numbers in the set is ...

  (7(n-6) +6(29))/n = 19

  7n +132 = 19n . . . . multiply by n, collect terms

  132 = 12n . . . . . . . . subtract 7n

  11 = n . . . . . . . . . . .  divide by 12

The value of n is 11.

DanielleElmas [232]3 years ago
4 0

Answer:11

Step-by-step explanation:

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SOLUTION:

Case: Hypothesis testing

Step 1: Null and Alternative hypotheses

\begin{gathered} H_0:\mu=P127.50 \\ H_1:\mu\leq P127.50 \end{gathered}

Step 2: T-test analysis

\begin{gathered} t=\frac{\hat{x}-\mu}{\frac{s}{\sqrt{n}}} \\ t=\frac{135-127.5}{\frac{75.25}{\sqrt{450}}} \\ t=2.144 \end{gathered}

Step 3: t-test with the significance level

\begin{gathered} t_{\alpha}=? \\ \alpha=0.05 \\ From\text{ }tables \\ t_{0.05}=1.654 \end{gathered}

Step 4: Comparing

t>t_{\alpha}

So tail to reject the null hypothesis. There is enough evidence at a 0.05 level of significance to claim that the mean spent is greater than P127.50.

Final answer:

Yes, there is evidence sufficient to conclude that the mean amount spent is greater than P127.50 per month at a 0.05 level of significance.

6 0
1 year ago
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Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

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