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jeyben [28]
2 years ago
14

HELP ASAP!!!!! Prove that the two circles shown below are similar.

Mathematics
1 answer:
Andreas93 [3]2 years ago
8 0

Answer:

They are both have similar radii becuse Circle B's is 4 and Circle D's is 2 so that means that Circle B is the same as D but just dialated.

Step-by-step explanation:

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What is the solution to -(6 m + 8) = 4(17 - m)?
icang [17]

Answer:

m=-38

Step-by-step explanation:

6 0
3 years ago
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Four times the larger of two consecutive even integers is ten less than the smaller. What is the larger of these two numbers?
anygoal [31]

Answer:

-4 is the larger integer

Step-by-step explanation:

n = smaller integer

n + 2 = larger integer

4(n+2) = n-10

4n + 8 =  n - 10

3n + 8 = -10

3n = -18

n = -6

n+2 = -4

7 0
3 years ago
The figure shows a cylinder of diameter 12cm and height = 15cm. A hole in the shape of cone is bored into one of its end. If the
Lisa [10]

Answer:

\bold{495\pi} \approx \bold{1555.088 cm^3}

Step-by-step explanation:

There was no figure but the question is clear

Volume of a cylinder is given by the formula \bold{\pi r^2h}\\

where r is radius of base of cylinder, h is the height

Volume of a cone is given by \bold{\frac{1}{3} \pi r^2 h}

where r is the radius of base of cone, h is the height

The radius of the cylinder = \frac{1}{2}(diameter) = \frac{1}{2}(12) = 6cm

Height of cylinder = 15cm

Volume of cylinder V_{cyl} = \pi (6)^2  15 = \pi (36)15 = \bold{540\pi}

Radius of cone = \frac{1}{2} (radius of cylinder) = \frac{1}{2}(6) = 3 cm

Height of cone same as height of cylinder = 15cm

Volume of cone, V_{cone} = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (3)^2 15 =  \frac{1}{3}(9)15\pi = \bold{45\pi}\\


Difference is the volume of the remaining solid

V_{cyl} - V_{cone} = 540\pi - 45\pi = \bold{495\pi} \approx \bold{1555.088 cm^3}



5 0
1 year ago
Joaquin is constructing the perpendicular bisector of ab. What should be his first step?
natali 33 [55]

Answer:

D. Open the compass so that the distance from the two points of the compass is wider than half the length of \over{AB}.

Step-by-step explanation:

To construct a perpendicular for \over{AB}, we must first take a compass & take the distance of its arms wider than half the length of \over{AB}.

This is done in order to get two intersecting arcs in the top & bottom of \over{AB} so that a perpendicular bisector can be drawn through it.

After two intersecting lines are drawn below & above \over{AB}, draw a line joining these 2 points through their points of intersection. The point where it intersects \over{AB} is the middle-most point of \over{AB} & now a perpendicular bisector of \over{AB} is constructed.

\rule{150pt}{2pt}

3 0
2 years ago
Simplify 6^3/6^2<br> A. 6<br> B. 1 1/2<br> C. 18<br> D. 256
MaRussiya [10]
The answer would be (A) 6
8 0
4 years ago
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