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1 year ago

HELP ASAP!!!!! Prove that the two circles shown below are similar.

Mathematics

1 answer:

Andreas93 [3]1 year ago

8 0

Answer:

They are both have similar radii becuse Circle B's is 4 and Circle D's is 2 so that means that Circle B is the same as D but just dialated.

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

2. What is the total surface area of the figure below 5.2 cm 6 cm 9 cm 6 cm 6 cm

babunello [35]

Answer:

193.2 cm²

Step-by-step explanation:

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2 years ago

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2 years ago

Solve the following equation and determine if it has one solution, no solution, or infinitely many solutions: 3x+1−3(x−1)=4

vaieri [72.5K]

Answer:

1/3 , only one solution

Step-by-step explanation:

3x-1 = 1-3x

3x-1 = -3x+1

6x-1 = 1

6x = 2

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7 0

3 years ago

Read 2 more answers

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

2 years ago