by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Answer:
it's A
Step-by-step explanation:
The domain is all the input values which is x|x=-5,-3,1,2,6
First, you need to analize and understand the problem, then you must choose and strategy. There is a wide variety of strategies to solve a mathematical problem, in this case, you can use the following, which is based on the information given above:
1. You have that t<span>he sum of three consecutive even integers is </span>
<span>, therefore, you can given the variable </span>
<span> to the first integer, the second even integer is </span>
<span> and the third one is </span>
<span>.
2. Calculate x:
</span>
<span>
</span>
<span> </span>
<span>
</span>
<span>
</span>
<span>
Therefore, the answer is:</span>
Answer:
Take a glass, and fill it completely with water.
Now, pour that water in a marked bowl and measure how much water is in the bowl, that amount of water will be 100% of the total water that the glass can have.
Now you need to pour 3/5 of the water back in the glass, it is easier for water until the water in the bowl is exactly 2/5 of the initial amount.
You can do this as follows.
2/5 = 0.4 or 40% in percentage form.
Then if the amount of water in the marked bowl is A, the amount of water that must remain in the marked bowl is A*0.4
Then drop the water in the glass until the water in the marked bowl is the quantity that you found previously.
In this way, you can be sure that the glass is 3/5 full of water.
