Answer:
1134.62 (THE SUM OF 20 TERMS)
Step-by-step explanation:
First we write out our given information:
a8=2a2
a11=18
an is an arithmetic sequence.
Where here an means the nth term of our sequence.
What does an arithmetic sequence mean? It means to get to the next term in your sequence you add a constant (c) each time:
an+1=an+c
Equivalently:
an+1−an(n+1)−n=c
So an is of slope c (c2 is another constant):
an=cn+c2
Where here c2=a0 (Substitute in n=0 and see why that has to be the case if we let a0 exist)
Now we use the other given information to try to come up with a solution.
Let n=2:
a2=2c+c2
Let n=8, using the above equation we have:
a8=8c+c2=2a2=4c+2c2
Let n=11
a11=18
a11=11c+c2
But a11−a8=(11c+c2)−(8c+c2)=3c
Hence, a11=3c+a8
a11=3c+4c+2c2=18
a11=3c+8c+c2=18
She can only but 14 movies because 18.50÷1.25= 14.8 and then 1.25×14=17.5
Answer:
A≈12.57cm²
Step-by-step explanation:
A=1
4πd2=1
4·π·42≈12.56637cm²
// Input value is usernum.
// This code snippet sums 1 + 3 + 5 + ... + usernum
// The answer is stored in the variable summedvalue.
N = (int) (usernum+1)/2; // maximum number of integers to be summed
int *v = malloc(N*sizeof(int)); // allocate storage for array v
// Calculate the number of loop counts and assign array v..
count = 0;
k = 1;
while (1) {
if (k>usernum) { // do not extend v beyond usernum
break;
}
v(count) = k; // assign an odd integer to v, including usenum
count++;
k += 2; // k is an odd number
if k>usernum { // handle usernum as odd or even
k = usernum;
}
}
n = count; // the size of array v.
// Calculate the sum in a for loop
summedvalue = 0; // initialize summedvalue
for (i=0; i<=n; i++) {
summedvalue += v(i);
}
