What is the range of possible sizes for x?

Mathematics

2 answers:

lana [24]3 years ago

7 0

Answer:

9.0 - 15.0

Step-by-step explanation:

Give Brainllest

Lelu [443]3 years ago

4 0

Answer:

yo can u help me with my other ones on my questions most recent profile or just comment sr i nned help in like 2 mins

Step-by-step explanation:

You might be interested in

Who knows this, Find m∠UTS, if m∠UTV=x+15, m∠VTS=140∘, and m∠UTS=15x+15

kakasveta [241]

Answer:

165

Step-by-step explanation:

First, m<UTS=m<UTV+m<VTS by Angle Addition Postulate. Then, you substitute all the values that you provided for the angles. 15x+15=x+15+140. You then solve for x.

15x+15=x+155

14x=140

x=10

You then plug back in 10 for X in the value of m<UTS. 15(10)+15=165

5 0

3 years ago

I've been trying to get an answer for this all day and don't know where to begin what is the answer like I have no clue

Shtirlitz [24]

so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.

we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.

$\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78$