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3 years ago

The diameter of a semicircle is 24.6 feet. What is the semicircles radius?

Mathematics

1 answer:

True [87]3 years ago

4 0

Answer:

12.3 feet

Step-by-step explanation:

all you have to understand is that a radius is half the diameter....

24.6/2=12.3

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Which function is the inverse of y = 1/4x^2 - 1, where x < 0

kykrilka [37]

Answer:

Step-by-step explanation:

25 x 25= 625

625-1= 624

B= y= -(200 + 1) which to the square root = 625

5 0

3 years ago

I need help on this one plzz

masya89 [10]

I’m pretty sure the answer is C

4 0

3 years ago

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Is (x + 5) a factor of f(x) = x^3 – 4x^2 + 3x + 7? Use either the remainder theorem or the factor theorem to explain your reason

stich3 [128]

ANSWER

Not a factor

EXPLANATION

The given polynomial has equation:

$f(x) = {x}^{3} - 4 {x}^{2} + 3x + 7$

According to the remainder theorem, if (x+5) is a remainder, then f(-5)=0.

Let us substitute x=-5 into the function and evaluate to see if it will simplify to zero.

$f( - 5) = {( - 5)}^{3} - 4 {( - 5)}^{2} + 3( - 5)+ 7$

$f( - 5) = - 125 - 100 - 15+ 7$

$f( - 5) = - 233$

Since the remainder is not zero, x+5 is not a factor of

$f(x) = {x}^{3} - 4 {x}^{2} + 3x + 7$

6 0

4 years ago

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16: Find the coordinates of the foci and the vertices, the eccentricity, the length of the latus rectum of the Hyperbola y^2-16x

Morgarella [4.7K]

Answer:

Foci $(0,\pm\frac{\sqrt{17}}{4})$

Vertices: $(0,\pm 1)$

Eccentricity, e= $\frac{\sqrt{17}}{4}$

Length of latus rectum= $\frac{1}{8}$

Step-by-step explanation:

We are given that

$y^2-16x^2=1$

$y^2-\frac{x^2}{(\frac{1}{4})^2}=1$

The equation of hyperbola is along y-axis because y is positive

Compare the equation with

$y^2/a^2-x^2/b^2=1$ (Along y-axis)

We get

a=1, b=1/4

$a^2+b^2=c^2$

$1+\frac{1}{16}=c^2$

$\frac{16+1}{16}=c^2$

$c^2=\frac{17}{16}$

$c=\pm \frac{\sqrt{17}}{4}$

Therefore,

The coordinates of foci= $(0,\pm c)=(0,\pm\frac{\sqrt{17}}{4})$

The coordinated of vertices= $(0,\pm a)=(0,\pm 1)$

Eccentricity, e=c/a

$e=\frac{\frac{\sqrt{17}}{4}}{1}=\frac{\sqrt{17}}{4}$

Length of latus rectum= $\frac{2b^2}{a}$

Length of latus rectum= $2\times \frac{1}{16}=\frac{1}{8}$

3 0

3 years ago

Which solid is a triangular pyramid?

adelina 88 [10]

Answer:

pyramid with triangular base

6 0

3 years ago

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