The answer is 11 and 14/33.
Answer:
see explanation
Step-by-step explanation:
(a)
Given
2k - 6k² + 4k³ ← factor out 2k from each term
= 2k(1 - 3k + 2k²)
To factor the quadratic
Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)
The factors are - 1 and - 2
Use these factors to split the k- term
1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )
1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term
= (1 - k)(1 - 2k)
1 - 3k + 2k² = (1 - k)(1 - 2k) and
2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)
(b)
Given
2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )
= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term
= (x - 2y)(2a + 3b)
Answer:
Round 3 the grandmas
Step-by-step explanation:
Answer:
4/5 24/30
Step-by-step explanation:
Suppose width is X
then length would be X+44
perimeter of rectangle = 2 (length + width)
substitute:
328 = 2 ( X+44 + X )
328 = 2 ( 2X + 44 )
328 = 4X + 88
328 - 88 = 4X
240 = 4X
240/4 = X
X = 60
substitute in the first and second line
width is X so width = 60 feet
length is X + 44 = 60 + 44 = 104 feet
