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2 years ago

(BRAINLIEST TO THE PERSON WHO HELPS ME WITH THESE THREE QUESTIONS)

Mathematics

1 answer:

tigry1 [53]2 years ago

7 0

Answer:

Cheryl's posts + 7 posts =Kevin Posts

K-C=7 or C+7+K I use them because C is Cheryl and K is Kevin

Operation=subtraction or addition because it could be K-C=7 or C+7+K

Cheryl wrote K-7=C posts

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In what year will the two quantities be equal?

Galina-37 [17]

Its the second because i did this already

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2 years ago

Round 3184.5641 to two decimal points?

Juli2301 [7.4K]

3185.56 because the 4 is less than 5 so there fire turns all those other numbers into zeros!000000

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2 years ago

-The dimensions of a rectangular garden were 2 m by 4 m. Each dimension was

posledela

Answer: 4 m

Step-by-step explanation:

Let the amount each dimension was increased by be x.

Now we can set up a equation.

(2+x)(4+x) = 48

8 + 2x + 4x + x^2 = 48

x^2 + 6x - 40 = 0.

We can factor the left side of the equation.

(x+10)(x-4) = 0.

Therefore, x equals either -10 or 4. Since you can't increase a dimension by a negative amount, x must equal to 4.

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1 year ago

Read 2 more answers

What is the equation of a quadratic function P with rational coefficients that

Phoenix [80]

Answer:

$P(x) = x^2-6x+58$

Step-by-step explanation:

Quadratic function is function of the form $P(x)=ax^2+bx+c$ where a, b and c are real numbers and $a\neq 0$

A number is said to be a rational number if it can be written in the form $\frac{u}{v}$ where u and v are integers and $v\neq 0$ .

A number is said to be a complex number if it can be written in the form u+iv where u and v are real numbers.

A number 'a' is said to be a zero of a function P(x) if $P(a)=0$

We know that if zero of a fraction is of form u+iv then its other zero is u-iv.

As 3+7i is a zero of the function, 3-7i is also its zero.

So, given equation is $\left ( x-(3-7i) \right )\left ( x-(3+7i) \right )$

$P(x)=\left ( x-(3-7i) \right )\left ( x-(3+7i) \right )\\=x^2-x(3+7i)-x(3-7i)+(3-7i)(3+7i)\\=x^2-3x-7ix-3x+7ix+9+49\\=x^2-6x+58$

4 0

3 years ago

John made this model to show \frac{4}{7}\times\frac{13}{9} 7 4 × 9 13 Using John's model, what is \frac{4}{7}\times\frac{13}

harkovskaia [24]

Answer:

$\frac{4}{7}\times\frac{13}{9} = \frac{52}{63}$

Step-by-step explanation:

Given

See attachment for model

Required

Determine $\frac{4}{7}\times\frac{13}{9}$ from the model

The model is represented by:

$\frac{4}{7}\times\frac{13}{9} = \frac{4}{7}\times\frac{9}{9} + \frac{4}{7}\times\frac{4}{9}$

To get: $\frac{4}{7}\times\frac{9}{9}$ , we consider the first partition

The number of shaded box is 63 ---- this represents the denominator

The total boxes shaded at the bottom is 36 ---- this represents the numerator

So, we have:

$\frac{4}{7}\times\frac{9}{9} = \frac{36}{63}$

To get: $\frac{4}{7}\times\frac{9}{9}$ , we consider the first partition

The number of shaded box is 63 ---- this represents the denominator

The total boxes shaded at the bottom is 16 (do not count the gray boxes) ---- this represents the numerator

So, we have:

$\frac{4}{7}\times\frac{4}{9} =\frac{16}{63}$

The equation becomes:

$\frac{4}{7}\times\frac{13}{9} = \frac{4}{7}\times\frac{9}{9} + \frac{4}{7}\times\frac{4}{9}$

$\frac{4}{7}\times\frac{13}{9} = \frac{36}{63} + \frac{16}{63}$

$\frac{4}{7}\times\frac{13}{9} = \frac{36+16}{63}$

$\frac{4}{7}\times\frac{13}{9} = \frac{52}{63}$

5 0

2 years ago