Answer:
The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days
P(X≤ 0.11) = 0.4404
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 0.10 inches
Given that the standard deviation of the population = 0.07inches
Let 'X' be a random variable in a normal distribution

<u><em>Step(ii):-</em></u>
The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days
P(X≤ 0.11) = P(Z≤0.1428)
= 1-P(Z≥0.1428)
= 1 - ( 0.5 +A(0.1428)
= 0.5 - A(0.1428)
= 0.5 -0.0596
= 0.4404
<u><em>Final answer:-</em></u>
The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days
P(X≤ 0.11) = 0.4404
Answer:
H is the circumcenter of triangle BCD
- CD = 2FD = 2*32 = 64
- CE = BE = 26
- HD = HC = 33
- GD = 1/2BD = 1/2(58) = 29
- HG = √HD ²-GD² = √33²-29² = 2√62 ≈ 15.75
- HF = √HD ²-FD² = √33²-32² =√65 ≈ 8.06
Answer:
the slope is 3
Step-by-step explanation:
Use the formula a^(x/n) = (n)√a^x (note it is a small n)
(5x^4y^3)^(2/9) = Small 9
Convert.
is your answer
hope this helps
The correct answer is B because 6 needs to be included.