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Iteru [2.4K]
2 years ago
12

Need help with number 3

Mathematics
1 answer:
GREYUIT [131]2 years ago
7 0
I think B is the correct answer. But I’m not sure 100%
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Jack wants to fill a rectangular box with sand. The length of the sand box is 3 feet, width is 6 inches, and height is 2.4 inche
Aleksandr-060686 [28]
Jack would need to buy 2 bags of sand.
To find the answer you first have to find the volume of the rectangular box which can be found using the formula length times width times height (remember that the numbers have to have the same unit so it would look like 3 times .5 times .2 if you convert them all the feet). the volume of the box is equal to .3
Then you could set the volume of the box equal to .15x to find how many boxes he would need. The formula would be .15x=.3
Divide by .15 to get x alone and you get 2 for the answer.
3 0
3 years ago
Read 2 more answers
Let u = <-6, 3>, v = <1, 9>. Find u - v. (5 points)
jeyben [28]

Answer:

u - v = <-7, -6>

Step-by-step explanation:

<-6,3> <1,9>

To get the result you just subtract the components of v from the components of u

<-6 - 1, 3 - 9>

<-7, -6>

8 0
3 years ago
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Subtract the rational expression 1/x^2-x-6 - x/x+2.
Aleksandr [31]

Answer:

Step-by-step explanation:

x² - x -6 = x²  + 2x - 3x - 3*2

            =x(x + 2) - 3(x + 2)

            = (x + 2 )(x - 3)

\frac{1}{x^{2}-x-6}+\frac{x}{x+2}=\frac{1}{(x +2 )(x - 3)}-\frac{x}{x + 2}\\

                      = \frac{1}{(x+2)(x-3)}-\frac{x(x-3)}{(x+2)(x-3)}\\\\=\frac{1-x(x-3)}{(x+2)(x-3)}\\\\=\frac{1-x^{2}+3x}{(x+2)(x-3)}\\\\

4 0
2 years ago
The number 28 please somebody help me...
MArishka [77]
Where is the persons info
8 0
3 years ago
The graph of y=f(x) is shown below. Draw the graph of y=-f(x)
valkas [14]

Answer:

y = -f(x): reflection over x axis

Step-by-step explanation:

y = -f(x): reflection over x axis

8 0
2 years ago
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