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Gnesinka [82]
3 years ago
12

Simplify -8+4(-3)/5 A.) -4 B.) 4 C.) -4/5

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0
C.) -4/5 because you simplify the top
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Answer:

Its 2.5 percent ladd enjoy

Step-by-step explanation:

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3 years ago
Which of the following correctly justifies statement 4 of the two-column proof?
slavikrds [6]

Answer:

D.Transitive property of equality

Step-by-step explanation:

We are given that segment JK is parallel to segment LM

We have to prove \angle 3=\angle 6

We have to find which option correctly justifies the statement 4 of the two - column proof.

1.Statement : JK is parallel to segment LM

Reason: Given

2.\angle 7\cong \angle 6

Reason: Vertical angles theorem

3.\angle 3\cong \angle 7

Reason:Corresponding angles theorem

4.\angle 3\cong \angle 6

Reason: Transitive property of equality.

If a=b and b=c then a=c

Hence, option D is true.

3 0
3 years ago
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A data set is normally disturbed. As data points are removed from both ends of the range, what happens to the display of data?
sergij07 [2.7K]

Answer: The display becomes skewed left.

Step-by-step explanation:

7 0
3 years ago
3. Which of the following quadratic equations has no solution? A) 0 = −2(x − 5)2 + 3 B) 0 = −2(x − 5)(x + 3) C) 0 = 2(x − 5)2 +
klemol [59]

Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

= 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

0 = 10x -50

-10x = -50

x = -50/-10

x = 5

Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

= 0

x + 5 = 0

x = -5

x + 3 = 0

x = -3

For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

3 0
3 years ago
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