Answer:
1: 2,20,200,2000,20000,2000000
2: 1,1,2,3,5,8,13,21,34
3:1,4,9,16,25,36,49,64
Step-by-step explanation:
1: 2,20,200,2000,20000,2000000
2: 1,1,2,3,5,8,13,21,34
3:1,4,9,16,25,36,49,64
Answer:
The answer is 1800!
Step-by-step explanation:
9514 1404 393
Answer:
{58, 59, 60} kg
Step-by-step explanation:
Let x represent the mass of the heavier cow. Then the mass of the lighter cow is 96 -x.
The inequalities regarding the relative masses are ...
x ≥ 96-x +20 . . . . . the heavy cow is at least 20 kg heavier
96 -x > 35 . . . . . . . the lighter cow is more than 35 kg
__
Adding x to the first inequality makes it ...
2x ≥ 116
x ≥ 58
Adding x-35 to the second inequality makes it ...
61 > x
So the mass of the heavier cow must be in the range ...
58 ≤ x < 61
Possible whole-number masses for the heavier cow are ...
58 kg, 59 kg, 60 kg
R and 81 are common factors so add them together and you get 9r;then your equation is 9r+11=29.After that you subtract 11 from 29 and then the equation is 9r=18.Then you divide 9 from 18 so you get r=2.