We will determine the roots of the given equation
by rational root theorem.
Rational root theorem states:
"If P(x) is a polynomial with integer coefficients, then p is a factor of the constant term of P(x) and q is a factor of the leading coefficient of P(x).Then all the possible values of
are the factors of the given polynomial".
Therefore, the given equation is:
![5x^3-7x+11=0](https://tex.z-dn.net/?f=5x%5E3-7x%2B11%3D0)
The factors of the leading coefficient of
= q = ![\pm 1, \pm 5](https://tex.z-dn.net/?f=%5Cpm%201%2C%20%5Cpm%205)
The factors of the constant = p = ![\pm 1, \pm 11](https://tex.z-dn.net/?f=%5Cpm%201%2C%20%5Cpm%2011)
So, the possible values of
.
Therefore, the roots of the given polynomial are
.
Pretty sure its b but I would check with someone else too
Answers;
Question 1 answer: The first and last option.
Question 1 explanation: 2(4x + 2) is 4x = 12 = 2 = 14 x 2 = 28 and 8x + 4 is 8 x 4 = 32 + 4 = 36 which is 8 more than 28 then, 3x = 9 + 2 + 3 x 2 = 28.
2(4x + 2) = 28 and 8x + 4 equals 36 which is 8 more and they're both equivalent to 2(3x + 2 + x) because 2(3x = 2 = x) equals 28.
Answer:
x=5 x=8 x=10
explanation:
anything greater than 5 would make the inequality true because 5×2=10