Please help me with this question.

Solve the right triangle. Round decimals to the nearest tenth

Tems11 [23]

Answer:

j = 19.6

k = 25.9

J = 49°

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relationships between sides and angles in a right triangle.

<h3>Analysis</h3>

The given side is opposite the given angle. We want to find the other acute angle and the missing sides: the hypotenuse, and the adjacent side. The relations involving the opposite side are ...

Sin = Opposite/Hypotenuse ⇒ Hypotenuse = Opposite/Sin

Tan = Opposite/Adjacent ⇒ Adjacent = Opposite/Tan

Of course, the acute angles in a right triangle are complementary, so we can use that fact to find the missing angle.

<h3>Application</h3>

Hypotenuse = Opposite/Sin

IJ = 17/sin(41°) ≈ 25.9

Adjacent = Opposite/Tan

IK = 17/tan(41°) ≈ 19.6

Angle J = 90° -41° = 49°

In summary, ...

j = 19.6

k = 25.9

J = 49°

8 0

2 years ago

Solve the system of equations.

Sedaia [141]

Answer:

(6,41)

x=6

y=41

Step-by-step explanation:

I did it algebraically to solve for x and y, and I also graphed both of them and found the point where they intersect. It’s in the image below.

Hope this helps! :)

4 0

3 years ago

Solve the following initial-value problem: (ex+y)dx+(3+x+yey)dy=0, y(0)=1 0=

alex41 [277]

Answer:

$e^x+xy+3y+(y-1)e^y=4$

Step-by-step explanation:

Given that

$(e^x+y)dx+(3+x+ye^y)dy=0$

Here

$M=e^x+y$

$N=3+x+ye^y$

We know that

M dx + N dy=0 will be exact if

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$

So

$\frac{\partial M}{\partial y}=1$

$\frac{\partial N}{\partial x}=1$

it means that this is a exact equation.

$\int d\left(e^x+xy+3y+(y-1)e^y\right)=0$

Noe by integrating above equation

$e^x+xy+3y+(y-1)e^y=C$

Given that

x= 0 then y= 1

$e^0+0+3+(1-1)e^1=C$

C=4

So the our final equation will be

$e^x+xy+3y+(y-1)e^y=4$

3 0

3 years ago

Please help me, I’ll give brainliest

kolbaska11 [484]

Answer:

x = 45

y = 5

Step-by-step explanation:

it is because

90/2 = 45

(90+10)/20 

(100)/20 = ,5

7 0

4 years ago

Two angry children 450 feet apart are headed straight towards each other—one at 15 feet per second and the other at 6 feet per s

sergiy2304 [10]

If the amount of time is x seconds, then 15*x is the amount ran by one child and 6*x is the amount ran for the other child due to that they add 15 or 6 feet for each second. In addition, since they are 450 feet apart, 15x+6x=450=21x. Dividing both sides by 21, we get x=around 21.4 seconds. Since the mother is always between them, when those two meet is when the three meet. Therefore, she runs 20* around 21.4= around 428.57 feet

6 0

3 years ago