40%=0.4
15*0.4
6
15-6
9 darts didn't hit the bull's eye
Using the probability and odds concepts, it is found that the odds against it containing a number greater than or equal to 7 is
.
- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- An odd is the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.
In the rack, there are 15 balls, numbered from 1 to 15. Of those, <u>6 are less than 7</u>(against it containing a number greater than or equal to 7 is equivalent to it containing a number less than 7), thus:
- There are 6 desired outcomes.
- There are 9 non-desired outcomes.
The odd is:

The odds against it containing a number greater than or equal to 7 is
.
A similar problem is given at brainly.com/question/21094006
1/2 is the probability, or 50%. There are 4 teams of S and B n the Y, 2 are B. so its 2/4