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love history [14]
2 years ago
5

One of the world's largest apples had a mass of 1,837 grams. Sue said the mass was greater than 2 kilograms.

Mathematics
1 answer:
natulia [17]2 years ago
6 0

Answer:

No

Step-by-step explanation:

1 Kilo = 1000 Grams. There are only 1837 Grams. This means that there is no way it is 2 kilos.

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You spent $10 on office supplies out of a $25 budget.What percent of your budget did you spend?
lana66690 [7]
You spent 40% of your budget. 

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6 0
3 years ago
Help pleasssseeee......(do all pls)
Ugo [173]
16. 5x^3 y^-5 • 4xy^3
20x^4y^-2

20x^4 • 1/y^2

=20x^4/y^2

17. -2b^3c • 4b^2c^2
= -8b^5c^3

18. a^3n^7 / an^4 (a^3 minus a = a^2 same as n^7 minus n^4 = n^3)
=a^2n^3

19. -yz^5 / y^2z^3

= -z^2/y

20. -7x^5y^5z^4 / 21x^7y^5z^2 (divide -7 to 21 and minus xyz)

= -z / 3x^2

21. 9a^7b^5x^5 / 18a^5b^9c^3

=a^2c^2 / 2b^4

22. (n^5)^4

n ^5 x 4
=n^20

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4 0
3 years ago
Read 2 more answers
Which number line shows the solution set for StartAbsoluteValue 2 p minus 4 EndAbsoluteValue greater-than-or-equal-to 6?
maks197457 [2]

Answer:

can u add a picture?

Step-by-step explanation:

8 0
2 years ago
What is the length of Line segment G D?<br><br> GD =___
olya-2409 [2.1K]
8/6 = 14/x
8x = 84
x = 10.5
The length of GD = 10.5
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4 0
3 years ago
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Darren wins a coupon for $4 off the lunch special for each of five days he pays $75 for his 5 lunch specials write and solve an
Valentin [98]

The original price for one lunch special is $19.

<em><u>Explanation</u></em>

The original price for one lunch special is  'p'  dollar.

He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay (p-4) dollar each day</u>.

So, the total amount needed to pay for 5 days = 5(p-4) dollar

Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....

5(p-4)= 75\\ \\ 5p-20=75\\ \\ 5p= 75+20\\ \\ 5p= 95\\ \\ p=\frac{95}{5}=19

So, the original price for one lunch special is $19.

8 0
3 years ago
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