One of the world's largest apples had a mass of 1,837 grams. Sue said the mass was greater than 2 kilograms.

Mathematics

1 answer:

natulia [17]2 years ago

6 0

Answer:

Step-by-step explanation:

1 Kilo = 1000 Grams. There are only 1837 Grams. This means that there is no way it is 2 kilos.

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In 2009, a town's population was about 9,000 residents. In 2014, the population was about 12,500 residents. Which linear model r

jek_recluse [69]

Answer:

The linear function that discribes the size of the population in function of the t in years is p = 700t - 1,397,300

Step-by-step explanation:

A linear function is defined by a line, so in order to determine the linear function we can use the two points that were given to us to create a line equation and use that as our linear function. The points given to us were (2009; 9000) and (2014; 12500), in this case the year is our value of "x" and the size of the population is our value of "y". The first step is to find the slope of the line which is given by:

m = (y2 - y1)/(x2 - x1)

m = (12500 -9000)/(2014 - 2009) = 3500/5 = 700

Then we can use the slope and the first point to build the equation:

p - 9000 = 700*(t - 2009)

p = 700t - 1406300 + 9000

p = 700t - 1397300

5 0

3 years ago

John ordered a large three topping pizza for $7. 50 and a large 8 topping pizza for $10. Write an equation in slope-intercept fo

yKpoI14uk [10]

to get the equation of any straight line, we simply need two points off of it, well, let's use the provided values hmmm

$\begin{array}{ccll} \stackrel{toppings}{x}&\stackrel{cost}{y}\\ \cline{1-2} 3 & 7.50\\ 8& 10 \end{array} \qquad\implies \qquad (\stackrel{x_1}{3}~,~\stackrel{y_1}{7.50})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{10}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{10}-\stackrel{y1}{7.50}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{3}}}\implies \cfrac{2.5}{5}\implies \cfrac{~~ \frac{25}{10}~~}{5}\implies \cfrac{25}{50}\implies \cfrac{1}{2}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7.50}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{3})\implies y-\cfrac{750}{100}=\cfrac{1}{2}(x-3) \\\\\\ y-\cfrac{15}{2}=\cfrac{1}{2}x-\cfrac{3}{2}\implies y=\cfrac{1}{2}x-\cfrac{3}{2}+\cfrac{15}{2}\implies y=\cfrac{1}{2}x-6$