<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
-3x+7<11
-3x<4
x>-4/3
So anything less than or equal to -4/3 does not belong to the solution set.
With your update:
"<span>The options is 4,-1,-5,and 0"
-5 does not belong to the solution set...</span>
Answer:
3%
Step-by-step explanation:
24÷400=.06
.06=6%
6%÷2=3%
Answer:
41.6 centimeters
Step-by-step explanation:
The right triangle formula: c^2 = a^2 + b^2
c is the hypotenuse side of the triangle
a and b are the legs of the triangle.
Find the hypotenuse : c^2 = (24)^2 + (34)^2
c = square root of ( (24)^2 + (34)^2)
c = square root of ( 576 + 1,156)
c = 41.6173
<span>126.4% of 158 = 199.712</span>
