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2 years ago

The distance from the Earth to the moon is about 239,000 miles. Rewrite the distance in scientific notation.

Mathematics

1 answer:

egoroff_w [7]2 years ago

4 0

Answer:

2.39 x 10^5 miles

Step-by-step explanation:

Although it is not usually written, there is always a .0 at the end of a number unless there is a specific decimal that was given.

So, the number here is 239,000.0 and if you count the number of spaces that the decimal needs to move in order to be in the correct spot for scientific notation (which is always after the first number), there is 5 spaces.

Therefore the answer is 2.39 x 10^5 miles.

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Use function notation to represent the average speed of the car on the interval from t = 2 to t = 7 .

Afina-wow [57]

Answer:

$Average\ Speed = \frac{s(7) - s(2)}{5}$

Step-by-step explanation:

Given

t = 2 to 7

Required

Find the average speed over these intervals

The function is not given; so, I'll represent the function as s(t)

When $t = 2;$

$s(t)= s(2)$

When $t = 7$

$s(t) = s(7)$

$Average\ Speed = \frac{Change\ in\ Distance}{Change\ in\ Time}$

This gives:

$Average\ Speed = \frac{s(7) - s(2)}{7 - 2}$

$Average\ Speed = \frac{s(7) - s(2)}{5}$

5 0

3 years ago

20. What is the greatest prime factor of 3^7+6^6 ?

mario62 [17]

Answer:

Step-by-step explanation:

3^7 = 2187

6^6 = 46656

46656+2187=48843

Prime factors of 48843: 3, 3, 3, 3, 3, 3, 67

Factor tree:

48843

| \

16281 3

| \

5427 3

| \

1809 3

| \

603 3

| \

201 3

| \

67 3

3 0

3 years ago

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

3 years ago

The product of two integers is -12 and the sum is -1. What are the numbers?

kupik [55]

Answer:

+3 and -4

Step-by-step explanation:

+3×-4=-12

and

-4+3=-1

3 0

3 years ago

PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST

ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0

3 years ago