Question

Find the equation of the tangent to the curve y = 4x³- 5x² + x - 3 at the point where it crosses the y axis.​

Answer 1

Answer:

y = x-3

Step-by-step explanation:

When the graph of this equation crosses the y - axis , the value of x is = 0.

 sub in zero to find this y value = -3

    so the point is (0, -3)

Now find the drivative of this equation....the derivative tells you the slope of the original graph at any given point

 derivative = 12x^2-10x+1        this , when x = 0 shows slope  = 1

    the equation then becomes   y = (1) x -3     or just  y = x-3

 See image below