5(-2/3)= what is the anwser to this

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

7 0

Answer:

-3.33333333333

Step-by-step explanation:

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Find the equilibrium point for the pair of demand and supply functions. Here q represents the

olya-2409 [2.1K]

The equilibrium point for the pair of demand and supply function is 100

We have been two linear function, one is linear supply function and other is linear demand function.

In general , linear supply function is given as:

Qs = x + yP

Where , Qs = quantity supplied

x = quantity

P = price

And linear demand function is given is :

Qd = x + yP

Where , Qs = quantity supplied

x = quantity

P = price

According to the question,

Linear supply function is q = 300 + 5x

And linear demand function is q = 4800 – 40x

To find the equilibrium point we will put two quantities equal, that is,

Qs = Qd

300 + 5x = 4800 – 40x

5x + 40x = 4800 – 300

45x = 4500

x = 100

Hence the equilibrium point is 100

Learn more about equilibrium point here : brainly.com/question/1915798

#SPJ9

4 0

1 year ago

What percent of 200 is .5?

sergiy2304 [10]

Is it 0.5? if so, the answer is 0.25%
if it is supposed to be just a 5 then the answer would be 2.5%

5 0

3 years ago

Ad is tangent to circle o at d. find ab. round to the nearest tenth if necessary

Naddik [55]

Check the picture below.

$\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{2^2\cdot 130}}{2}\implies AB=\cfrac{-6 \pm 2\sqrt{130}}{2}
\\\\\\
AB=-3\pm\sqrt{130}\implies AB=
\begin{cases}
\boxed{-3+\sqrt{130}}\\\\
-3-\sqrt{130}
\end{cases}$

since the distance AB cannot be a negative value, thus is not -3-√(130).