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4 years ago

HELP IN GEOMETRY......

Mathematics

1 answer:

OleMash [197]4 years ago

4 0

2. QM is congruent to QN
4, All right angles are congruent
5.QX is congruent to QX
6.SAS congruence
7.MX is congruent to NX

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kevin and his father have collected1,456 different coinsover the years.They have a coin album that holds 30 coinson a page. If t

Simora [160]

48.54

hope this helped

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3 years ago

Read 2 more answers

Trevor solved the system of equations below. What mistake did he make in his work? 2x + y = 5 x − 2y = 10 y = 5 − 2x x − 2(5 − 2

Arturiano [62]

$2x+y=5 \\
x-2y=10 \\ \\
y=5-2x \\
x-2(5-2x)=10 \\
x-10+4x=10 \\
5x-10=10 \\
\boxed{5x=0} \Leftarrow \hbox{the mistake, it should be 5x=20} \\
x=0 \\ \\
2(0)+y=5 \\
y=5$

If 2x+y=5, then y=5-2x, so he substituted 5-2x correctly.
x+4x=5x, so he combined like terms correctly.
If 5x-10=10, then 5x=10+10 -> 5x=20, so he subtracted 10 from the right side instead of adding 10 to the right side.

The answer is C.

Here's the correct solution:
$2x+y=5 \\
x-2y=10 \\ \\
y=5-2x \\
x-2(5-2x)=10 \\
x-10+4x=10 \\
5x-10=10 \\
5x=10+10 \\
5x=20 \\
x=\frac{20}{5} \\
x=4 \\ \\
y=5-2x \\
y=5 - 2 \times 4 \\
y=5-8 \\
y=-3 \\ \\
(x,y)=(4,-3)$

5 0

3 years ago

A factory creates 80 kilograms of steel in 1 hour. How many kilograms does the factory make in 4 hours?

fgiga [73]

Answer:

320

Step-by-step explanation:

80*4

6 0

2 years ago

2. A function fis graphed below, which consists of two semicircles and two linear pieces.

ivolga24 [154]

Ist b hope that helps

8 0

3 years ago

4. Assume that the chances of a basketball player hitting a 3-pointer shot is 0.4 and the probability of hitting a free-throw is

vovikov84 [41]

Answer:

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

Step-by-step explanation:

For each 3-pointer shot, there are only two possible outcomes. Either the player makes it, or the player does not. The same is valid for free throws. This means that both the number of 3-pointers and free throws made are given by binomial distributions.

Since 3-pointers and free throws are independent, first we find the probability of making exactly 3 3-pointers out of 10, then the probability of making exactly 5 free throws out of 10, and then the probability that the player will make exactly 3 3-pointers and 5-free throws is the multiplication of these probabilities.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of making 3 3-pointers out of 10:

The chances of a basketball player hitting a 3-pointer shot is 0.4, which means that $p = 0.4$ . So this is $P(X = 3)$ when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.21499$

Probability of making 5 free throws out of 10:

The probability of hitting a free-throw is 0.65, which means that $p = 0.65$ . The probability is $P(X = 5)$ when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{10,5}.(0.65)^{5}.(0.35)^{5} = 0.15357$

Calculate the probability that the player will make exactly 3 3-pointers and 5-free throws.

0.21499*0.15537 = 0.0334

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

5 0

3 years ago