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4 years ago

HELP IN GEOMETRY......

Mathematics

1 answer:

OleMash [197]4 years ago

4 0

2. QM is congruent to QN
4, All right angles are congruent
5.QX is congruent to QX
6.SAS congruence
7.MX is congruent to NX

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A constant of proportionality can also be considered a(n) unit rate. y-value. x-value. ratio.

lilavasa [31]

Answer:

A. Unit rate.

Step-by-step explanation:

We have been given a statement and we are supposed to choose the correct option for our given statement.

Statement:

A constant of proportionality can also be considered a(n) <u> </u> .

Since we know that constant of proportionality represents the amount by which two proportional quantities vary.

Two quantities are directly proportional, when they are in form $y=kx$ , where k represents the constant of proportionality.

We can represent this proportion also as: $k=\frac{y}{x}$

Since k represents the quotient of y and x, so the value of k represents the unit rate for two quantities y and x, therefore, a constant of proportionality can also be considered an unit rate.

7 0

4 years ago

Read 2 more answers

Executives from Six Flags, a well-known amusement park chain, had interest in constructing a Six Flags theme park in a location

natima [27]

Answer:

The mean of the sampling distribution for the sample proportion when taking samples of size 500 from this population is equal to 0.248.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Of the 500 people sampled, 124 said that they would be interested in purchasing season tickets to a Six Flags in Ames.

This means that $p = \frac{124}{500} = 0.248$

The mean of the sampling distribution for the sample proportion when taking samples of size 500 from this population is equal to

By the Central Limit Theorem, it is equal to the sample proportion of 0.248.

4 0

3 years ago

Evaluate f(a + h) − f(a) for the quadratic function f(x) = x2 + 5. f(a + h) − f(a)

Butoxors [25]

$f(x)=x^2+5\\\\f(a+h)=(a+h)^2+5=a^2+2ah+h^2+5\\\\f(a)=a^2+5\\\\f(a+h)-f(a)=(a^2+2ah+h^2+5)-(a^2+5)=a^2+2ah+h^2-a^2-5=2ah+h^2$

8 0

3 years ago

What is the value of a3 in the sequence?<br> 5, 10, 20, 40, 80...

laiz [17]

I can’t see a3 do you have a picture

4 0

3 years ago

If (x-y)^2=71 and x^2+y^2=59 what is the value of xy?

Lena [83]

Solve the equations
first one
take the sqrt of both sides
x-y=√71
add y to both sides
x=y+√71
sub y+√71 for x in other part

(y+√71)²+y²=59
y²+2y√71+71+y²=59
2y²+2y√71+71=59
minus 59 both sides
2y²+2y√71+12=0
factor out 2
2(y²+y√71+6)=0
use quadratic equation or something
y= $\frac{- \sqrt{71}- \sqrt{47} }{2}$ and $\frac{- \sqrt{71}+ \sqrt{47} }{2}$

sub those for x

x=y+√71
note: √71=(2√71)/2

x= $\frac{- \sqrt{71}- \sqrt{47} +2\sqrt{71}}{2}$ , $\frac{\sqrt{71}- \sqrt{47}}{2}$
or
x= $\frac{- \sqrt{71}+ \sqrt{47} +2\sqrt{71}}{2}$ , $\frac{\sqrt{71}+ \sqrt{47}}{2}$

xy= $\frac{\sqrt{71}- \sqrt{47}}{2}$ times $\frac{-\sqrt{71}- \sqrt{47}}{2}$ or $\frac{\sqrt{71}+ \sqrt{47}}{2}$ times $\frac{-\sqrt{71}+ \sqrt{47}}{2}$

the result is -6 both times

xy=-6

5 0

4 years ago