Answer with explanation:

Average Height of tallest Building in San Francisco

Average Height of tallest Building in Los Angeles

→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco
=233.9-197.8
=36.1
⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.
⇒Part B
Mean absolute deviation for the 10 tallest buildings in San Francisco
|260-197.8|=62.2
|237-197.8|=39.2
|212-197.8|=14.2
|197 -197.8|= 0.8
|184 -197.8|=13.8
|183-197.8|=14.8
|183-197.8|= 14.8
|175-197.8|=22.8
|174-197.8|=23.8
|173 -197.8|=24.8
Average of these numbers

Mean absolute deviation=23.12
The hurdle and runner form a right triangle (see attached picture) such that
sin(30°) = <em>h</em> / (5 ft)
and
cos(30°) = <em>x</em> / (5 ft)
where <em>h</em> is the height of the hurdle and <em>x</em> is the horizontal distance from where the runner jumps to the hurdle. So
<em>h</em> = (5 ft) sin(30°) = 5/2 ft = 2.5 ft
<em>x</em> = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft
3c + b.....when c = -7 and b = 4
3(-7) + 4 =
-21 + 4 =
- 17 <===
Answer:
(-8,8)
Step-by-step explanation:
Simplify |n| + 4 < 12. To do this, subtract 4 from both sides. This results in:
|n| < 8. The solution set includes all real numbers between -8 and 8, but not -8 itself or 8 itself.
Answer:
to be entirely honest i do not know
Step-by-step explanation: