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3 years ago

URGENT 15 POINTS!!!!What is the solution of the system?

2 answers:

8 0

The elimination method is a sufficient way to solve problems.

2x+y= 20
6x-5y=12

Add 5y to the one equation.

2x+6y= 20
6x= 12

Subtract 2x from both sides.

6y= 20
4x= 12

Divide 6 by 20.
y= 3.3

Divide 4 by 12.
x= 3

I hope this helped you!

Brainliest answer is appreciated!

Mila [183]3 years ago

8 0

I don't know if this helps but...
(2x4)+6=10
(6x12) - (5x12) = 12

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What is a35 for the arithmetic sequence presented in the table below?

Kryger [21]

Answer: choice B) a35 = -118

=====================================================

Explanation:

When n = 5, an = 32 as shown in the first column of the table. This means the fifth term is 32. Plug in those values to get

an = a1+d(n-1)

32 = a1+d(5-1)

32 = a1+4d

Solve for a1 by subtracting 4d from both sides

a1 = 32-4d

We'll plug this in later

Turn to the second column of the table. We have n = 10 and an = 7. Plug those values into the formula

an = a1+d(n-1)

7 = a1 + d(10-1)

7 = a1+9d

Now substitute in the equation in which we solved for a1

7 = a1+9d

7 = 32-4d+9d ... replace a1 with 32-4d

7 = 32+5d

5d = 7-32

5d = -25

d = -25/5

d = -5

This tells us that we subtract 5 from each term to get the next term.

Use this d value to find a1

a1 = 32-4d

a1 = 32-4*(-5)

a1 = 32+20

a1 = 52

The first term is 52

--------------

The nth term formula is therefore

an = 52 + (-5)(n-1)

which simplifies to

an = -5n + 57

To check this result, plug in n = 5 to find that a5 = 32. Similarly, you'll find that a10 = 7 after plugging in n = 10. I'll let you do these checks.

--------------

Replace n with 35 to find the 35th term

an = -5n + 57

a35 = -5(35) + 57

a35 = -175 + 57

a35 = -118

7 0

2 years ago

Please help me with this

kirill [66]

Answer:

15/2 or 7.5

Step-by-step explanation:

$5/6 (x + 1/2 + 4)$

distribute 5/6 to each number

$5/6x + 5/12 + 10/3$

change the fraction 10/3 so that it will have the same denominator as 5/12

$\frac{10}{3} *4$ = 40/12

$5/6x + 5/12 + 40/12\\5/6x + 45/12$

divide both sides by 5/6

$x = 9/2$

$5/6*9/2+5/12+10/3 = \frac{15}{2}$

3 0

1 year ago

Philip made a total of 9 bracelets and necklaces from 120 inches of cord. He used 8 inches of cord for each bracelet and 20 inch

Viktor [21]

Answer:

So Philip made 5 bracelets and 4 necklaces.

Step-by-step explanation:

Let x = number of bracelets and y = number of necklaces.

Since we have a total of 9 bracelets and necklaces,

x + y = 9 (1)

Also, we have 8 inches of cord for each bracelet and 20 inches of cord for each necklace, then the total length for the bracelet is 8x and that for the necklace is 20y.

So, the total length for both is 8x + 20y. Since the total length of cord used is 120 inches,

8x + 20y = 120 (2)

Simplifying it we have

2x + 5y = 30 (3).

Writing equations (1) and (3) in matrix form, we have

$\left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}9\\30\end{array}\right]$

Using Cramer's rule to solve for x and y,

$x = det \left[\begin{array}{ccc}9&1\\30&5\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\$

x = (9 × 5 - 30 × 1) ÷ (1 × 5 - 1 × 2)

x = (45 - 30) ÷ (5 - 2)

x = 15 ÷ 3

x = 5

$y = det \left[\begin{array}{ccc}1&9\\2&30\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\$

y = (30 × 1 - 9 × 2) ÷ (1 × 5 - 1 × 2)

y = (30 - 18) ÷ (5 - 2)

y = 12 ÷ 3

y = 4

So Philip made 5 bracelets and 4 necklaces.

3 0

3 years ago

Reduce the fraction -20t^5 u^2 v^3 over 48t^7 u^4 v

timofeeve [1]

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5 0

3 years ago

Helpppppppppppppppppppppppp

Genrish500 [490]

Answer:

Is none a answer?

Step-by-step explanation:

They dont have a relashionship

8 0

2 years ago