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Answer:
Hence, 0.00000103 can be expressed as 
.
Step-by-step explanation:
- Given 0.00000103
- Move the decimal point so that the factor is greater than or equal to 1 but less than 10 .
- Then count n and write no. as a product with a power of 10 .
Step 1 of 1
Consider 0.00000103,
1.03
Decimal has moved 6 places to right.
The power will be negative as the original no. is less than 1 .
I'm assuming there is a graph with both functions plotted. The solution would be the point at which these two functions intersect. That coordinates of x and y for that point will yield the solutions for x and y that solve the system of equations.
We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.
