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1 year ago

Please help me with this math problem!! :) Will give brainliest!!

Mathematics

1 answer:

Gnoma [55]1 year ago

5 0

Answer:

Your answer is x=-13/3

Step-by-step explanation:

RS and QT are equal knowing this your equation would be x=4x+13. you get -3x=13 when 4x get cancelled out, divide both side by 3 and you get -13/3

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Can someone factor this problem for me?

Likurg_2 [28]

Your factored answer will be

(3x-4y) (x-5y)

hope this helps

8 0

2 years ago

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Use pie= 22/7 to approximate the circumference of a circle whose diameter is 28 inches.

Nata [24]

Answer:

88 inches

Step-by-step explanation:

formula for circumference: 2pir or pi*diameter

22/7*28=88

88 inches

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1 year ago

3 out of 4 students like to eat breakfast at school. What percent of students like to eat breakfast?

melomori [17]

Answer:

The answer is that 75% of the student like to eat breakfast.

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2 years ago

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If you are offered one slice from a round pizza (in other words, a sector of a circle) and the slice must have a perimeter of 24

VARVARA [1.3K]

Answer:

A 12 in diameter will reward you with the largest slice of pizza.

Step-by-step explanation:

Let $r$ be the radius and $\theta$ be the angle of a circle.

According with the graph, the area of the sector is given by

$A=\frac{1}{2}r^2\theta$

The arc lenght of a circle with radius $r$ and angle $\theta$ is $r \theta$

The perimeter of the pizza slice is composed of two straight pieces, each of length r inches, and an arc of the circle which you know has length s = rθ inches. Thus the perimeter has length

$2r+r\theta=24 \:in$

We need to express the area as a function of one variable, to do this we use the above equation and we solve for $\theta$

$2r+r\theta=24\\r\theta=24-2r\\\theta=\frac{24-2r}{r}$

Next, we substitute this equation into the area equation

$A=\frac{1}{2}r^2(\frac{24-2r}{r})\\A=\frac{1}{2}r(24-2r)\\A=12r-r^2$

The domain of the area is

$0$

To find the diameter of pizza that will reward you with the largest slice you need to find the derivative of the area and set it equal to zero to find the critical points.

$\frac{d}{dr} A=\frac{d}{dr}(12r-r^2)\\A'(r)=\frac{d}{dr}(12r)-\frac{d}{dr}(r^2)\\A'(r)=12-2r$