Answer:
3x+2y+11
Step-by-step explanation:
I hope this helps
your welcome
A normal vector is the set of coefficients of x, y, and z when the equation is written in standard (or general) form.
Subtracting the left side, we have
... 2(8 -y) -z +5(x -2) = 0
... 16 -2y -z +5x -10 = 0
... 5x -2y -z +6 = 0 . . . . . general form
A normal vector is (5, -2, -1).
An=-31+(n-1)-11 find the eleventh term
a11 = -31 + (-11) (11-1)
a11 = -31 +-11(10)
a11 =-31 +-110
a11 = -142
Answer:
under
Step-by-step explanation:
change the underminator, we have
7×(x-2)-4×(3x+5)=-3×7×4
7x-14-12x-20=-84
-5x=-50
x=10
Answer:
40%
Step-by-step explanation:
3/5=60%
100%-60%=40%
