Answer:
Step-by-step explanation:
Given
m∠COD=8x+13,
m∠BOC=3x-10, and
m∠BOD=12x-6
The following addition property is true;
<BOD = <BOC + <COD
Substitute
12x-6 = 3x-10+8x+13
12x-6 = 11x+3
12x-11x = 3+6
x = 9
Get <BOD
<BOD = 12x-6
<BOD = 12(9)-6
<BOD = 108-6
<BOD = 102°
Answer:
x = 65.03°
Step-by-step explanation:
To solve for x, we have to apply trigonometric ratio.
Recall: SOH CAH TOA
From the diagram, we know the following:
Reference angle = x
Hypotenuse = 45
Adjacent = 19
Since we know the Hyp and Adj, we would apply CAH, which is:
Cos x = Adj/Hyp
Plug in the values
x = 65.0250346°
x = 65.03° (nearest hundredth)
We are tasked to solve the value of p(8a) in the expression p(x)=3x^2-4.
This means that what would find the value of the expression when x=8a. To solve this, we simply substitute the value of x in the expression.
p(x)=3x^2-4
p(8a)=3(8a)^2-4
p(8a)=3(64a^2)-4
p(8a)=192a^2-4
Answer:
10y-12
Step-by-step explanation:
Answer:
The area that she painted = 896 mm^2
Step-by-step explanation:
Given:
The given figure is a pyramid with square base.
Here we need to find the surface area of the figure that need to be painted.
Surface area of a square pyramid = (S×S) + 2×S×L square.units
Where, S = side of the base L = slant height of the pyramid.
Now we have to plug in the given values.
Here S = 14, L =25
Plug in these values into the formula
= (14*14) + 2*14*25
= 196 + 700
= 896 mm^2
The area that she painted = 896 mm^2
Hope this will helpful.
Thank you.
