The temperature of a substance in an experiment changes by −8.7°F from 10 a.m. to 1 p.m. At 5 p.m., the temperature is 33.5°F. I

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The temperature of a substance in an experiment changes by −8.7°F from 10 a.m. to 1 p.m. At 5 p.m., the temperature is 33.5°F. I

t is 2/3 of what the temperature was at 1 p.m. What was the temperature at 10 a.m. of the substance? Enter your answer as a decimal in the box.
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Mathematics

1 answer:

bonufazy [111] · Answer 1 · 2022-12-18T08:36:42+03:00

The temperature of the substance at 10am = 63.95°F

Let the temperature at 10 am be x

The temperature changes by −8.7°F from 10 a.m. to 1 p.m

The temperature at 1 pm = x - 8.7

At 5 p.m., the temperature is 33.5°F

The temperature at 5 pm = 33.5°F

The temperature at 5 pm is 2/3 of what the temperature was at 1 p.m

$33.5 = \frac{2}{3} ( x-8.7 )$

Solve for x

3(33.5) = 2(x - 8.7)

110.5 = 2x - 17.4

2x = 110.5 + 17.4

2x = 127.9

x = 127.9/2

x = 63.95°F

The temperature of the substance at 10am = 63.95°F

Learn more here: brainly.com/question/25522357