Question

The temperature of a substance in an experiment changes by −8.7°F from 10 a.m. to 1 p.m. At 5 p.m., the temperature is 33.5°F. It is 2/3 of what the temperature was at 1 p.m. What was the temperature at 10 a.m. of the substance? Enter your answer as a decimal in the box.
PLS HELP

Answer 1

The temperature of the substance at 10am  =  63.95°F

Let the temperature at 10 am be x

The temperature changes by −8.7°F from 10 a.m. to 1 p.m

The temperature at 1 pm = x  -  8.7

At 5 p.m., the temperature is 33.5°F

The temperature at 5 pm = 33.5°F

The temperature at 5 pm is 2/3 of what the temperature was at 1 p.m

$33.5 = \frac{2}{3} ( x-8.7 )$

Solve for x

3(33.5)  =  2(x  -  8.7)

110.5  =  2x  -  17.4

2x  =  110.5 +  17.4

2x   =  127.9

x   =  127.9/2

x   =  63.95°F

The temperature of the substance at 10am =  63.95°F

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