There are a few relations related to tangents and secants that you are expected to remember. These problems make use of those.
1. When chords cut each other, the product of the segment lengths of one of them is equal to the product of the segment lengths of the other. Here, one of the chords is a diameter. That is special in that it is the bisector of any chord it crosses at right angles. That means ...
x·x = 2·6
x = √12 = 2√3
2. Secants from an external point have the same product of measures to the near and far intersection points with the circle. Since there is only one intersection point with a tangent, the near and far lengths are the same.
4·(4+8) = x·x
x = √48 = 4√3
Answer:
169.23m
Step-by-step explanation:.
Let's calculate the base of the cliff. Using SOH CAH TOA identity
Height (opposite) = 142n
Angle of depression = 40°
Required
Base of the cliff
Tan theta = opposite/adjacent
Tan 40 = 142/x
x = 142/tan40
x = 142/0.8391
x = 169.23m
Hence the base of the cliff is 169.23m long
Answer:
Yes
Step-by-step explanation:
Yes. Explanations vary. Sample explanation: The weight itself doubles, so
any measurement of the weight using the same units will also double. We
can also see that by saying if the weight is x pounds, then double that weight
would be 2x pounds. The weight in kilograms will be x ÷ 2.2, and the double
weight will be or (2x) ÷ 2.2 2(x ÷ 2.2), which is also double.
One and a half gallons. (1.5 gallons)
False, The F(x) = Logb X is not a set of all real numbers since the domain can be other numbers
