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3 years ago

(f/h)(2) f(x)=3x-4 h(x)=8-3x

Mathematics

1 answer:

kotegsom [21]3 years ago

3 0

Answer:

Step-by-step explanation:

find f(2)

f(2) = 3(2) - 4 = 6 - 4 = 2

Now find h(2)

h(2) = 8 - 3(2) = 8 - 6 = 2

Now find f(2)/h(2)

2/2 = 1

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Answer:

25d +10m = the amount he owed on a recent rental

Step-by-step explanation:

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What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

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3 years ago

write a linear equation that has a slope of 1/2 and a y-intercept at the origin. (y=1/2x) (y=0x+1/2) (y=1/2x+1/2) (y=-1/2x)

Nesterboy [21]

Answer:

The linear equation with given slope and y-intercept is:

Option 1: $y = \frac{1}{2}x$

Step-by-step explanation:

The slope-intercept form of equation is given by:

$y = mx+b$

Here

m is the slope of the line and b is the y-intercept.

Given that

Slope of line is 1/2 so m = 1/2

And y-intercept is on origin so b = 0

Putting the values we get

$y = \frac{1}{2}x+0\\y = \frac{1}{2}x$

Hence,

The linear equation with given slope and y-intercept is:

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