Answer:
9. 
8. 
7. 
Step-by-step explanation:
![\displaystyle [x - h]^2 - [y - k]^2 = r^2 → Hyperbola\:Equation \\ [x - h]^2 + [y - k]^2 = r^2 → Circle\:Equation \\ [h, k] → Centre](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Bx%20-%20h%5D%5E2%20-%20%5By%20-%20k%5D%5E2%20%3D%20r%5E2%20%E2%86%92%20Hyperbola%5C%3AEquation%20%5C%5C%20%5Bx%20-%20h%5D%5E2%20%2B%20%5By%20-%20k%5D%5E2%20%3D%20r%5E2%20%E2%86%92%20Circle%5C%3AEquation%20%5C%5C%20%5Bh%2C%20k%5D%20%E2%86%92%20Centre)
According to the equations in the exercises, in the parentheses, ALL NEGATIVE SIGNS give the OPPOSITE terms of what they REALLY are, so be EXTREMELY CAREFUL with your translations:
9. [4, 11]
+ 3 + 4
_____
[7, 15] → (x - 7)² and (y - 15)²
8. [−2, 8]
+ 3 + 2
_____
[1, 10] → (x - 1)² and (y - 10)²
7. [−8, −14]
+ 3 - 5
______
[−5, −19] → (x + 5)² and (y + 19)²
** NOTISE THAT THE RADII <em>NEVER</em><em> </em>ALTER.
I am joyous to assist you anytime.
A. 24 miles
Explanation:
the area inside a circle is given by:

where r is the radius of the circle.
In this problem, we know the circular area:

So we can re-arrange the equation above to find r, the radius:

so, the radius of the circular area is 24 miles.
Answer:
u => 4,028
Step-by-step explanation:
To find the answer, we have the following formula:
u => m - t (alpha, n-1) * [sd / (n) ^ (1/2)]
where m is the mean.
where sd is the standard deviation.
where n is the sample size.
t is a parameter that depends on the confidence interval and the sample size.
alpha = 1 - ci
ci = 90% = 0.9
Therefore, alpha = 1 - 0.9 = 0.1.
n - 1 = 25 - 1 = 24
So it would come being t (0.1, 24), if we look in the table, which I will attach the value of t is equal to 1.318.
We know the rest of the values, m = 4.05; sd = 0.08; n = 25
u => 4.05 - 1,318 * [0.08 / (25) ^ (1/2)]
u => 4.028
Which means that the interval with a 90% confidence of the wall thickness measurement is:
u => 4.028
Observe the graph below. This graph represents the scenario.
The question is ill formated, the complete question is
In a simulation, a moving object accelerates from rest to 4 meters per second in 2 seconds. For the following three seconds, it increases linearly until it reaches a speed of 10 meters per second. Following three seconds at that speed (acceleration = 0), the item progressively decelerates until it comes to rest two seconds later. Draw the graph of this scenario for 10 seconds?
I'll describe how the graph may show.
It will move diagonally upward from time 0 to 2 seconds until it reaches the y axis at a speed of 4 m/s.
Then, from 2 to 5, the position will move up diagonally until it reaches the y axis at a speed of 10 m/s.
The next 5 to 8 seconds will be horizontal.
After that, it will descend diagonally.
Observe the graph below. This graph represents the scenario.
Learn more about Acceleration here-
brainly.com/question/21509870
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