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2 years ago

Eden find this and help me

Mathematics

2 answers:

brilliants [131]2 years ago

8 0

Answer:

im good at math i could help.

Step-by-step explanation:

FromTheMoon [43]2 years ago

5 0

Answer:

HELP PLS

Step-by-step explanation:

brainly.com/question/20139113

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Please help! if anybody is good at equivalent polynomial expressions please help!!

scoundrel [369]

The one you have highlighted is correct

7 0

3 years ago

A circle with radius 6 has a sector with a central angle of 48 what is the area of the sector

inn [45]

Answer:

≈ 15.08 units²

Step-by-step explanation:

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

= πr² × $\frac{48}{360}$ ( r is the radius )

= π × 6² × $\frac{48}{360}$

= 36π × $\frac{48}{360}$ = π × $\frac{48}{10}$ = $\frac{48\pi }{10}$ ≈ 15.08

5 0

3 years ago

Read 2 more answers

Prove that if a, b ∈ n, then the supremum i.e. the least upper bound of {a, b} is the lcm(a, b).

WINSTONCH [101]

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────▐▌──────────▐▌────
────█▌▀▄──▄▄──▄▀▐█────
───▐██──▀▀──▀▀──██▌───
──▄████▄──▐▌──▄████▄──

6 0

3 years ago

Can someone produce SPSS results by including the the intercept (a.k.a. the constant), standard error of estimate, unstandardize

Firlakuza [10]

Answer:these are all odd

Step-by-step explanation:

the p-value for the unstandardized coefficient, R-square, Beta (i.e. standardized regression coefficient) using Excel with this given data?

Overall: 3.4, 2.9, 2.6, 3.8, 3.0, 2.5, 3.9, 4.3, 3.8, 3.4, 2.8, 2.9, 4.1, 2.7, 3.9, 4.1, 4.2, 3.1, 4.1, 3.6, 4.3, 4.0, 2.1, 3.8, 2.7, 4.4, 3.1, 3.6, 3.9, 2.9, 3.7, 2.8, 3.3, 3.7, 4.2, 2.9, 3.9, 3.5, 3.8, 4.0, 3.1, 4.2, 2.9, 3.9, 3.5, 3.8, 4.0, 3.1, 4.2, 3.0, 4.8, 3.0, 4.4, 4.4, 3.4, 4.0, 3.5

Teach: 3.8, 2.8, 2.2, 3.5, 3.2, 2.7, 4.1, 4.2, 3.7, 3.7, 3.3, 3.3, 4.1, 3.1, 2.9, 4.5, 4.3, 3.7, 4.2, 4.0, 3.7, 4.0 2.9, 4.0, 3.3, 4.4, 3.4, 3.8, 3.7, 3.1, 3.8, 3.2, 3.5, 3.8, 4.4, 3.7, 4.00, 3.4, 3.2, 3.8, 3.7, 4.3, 3.4, 4.0 3.1, 4.5, 4.8, 3.4, 4.2, 3.4

Exam: 3.8, 3.2, 1.9, 3.5, 2.8, 3.8, 3.8, 4.1, 3.6, 3.6, 3.5, 3.3, 3.6, 3.8, 3.8, 4.2, 4.1, 4.0, 4.3, 4.2, 4.0, 4.1, 2.7, 4.4, 4.4, 4.3, 3.6, 4.1, 4.2, 3.6, 4.4, 3.4, 3.2, 3.7, 4.3, 4.1, 3.7, 4.0, 3.6, 4.0, 3.7, 4.2, 4.2, 4.1, 3.2, 4.5, 4.3, 3.6, 4.00, 3.9

Knowledge: 4.5, 3.8, 3.9, 4.1, 3.5, 4.2, 4.5, 4.7, 4.1, 4.1, 3.9, 3.9, 4.0, 4.1, 4.5, 4.5, 4.5, 4.5, 4.7, 4.0, 4.5, 4.6, 3.7, 4.1, 3.6, 4.4, 3.3, 3.8, 4.2, 3.8, 4.0, 3.1, 4.4, 4.3, 5.00 4.2, 4.5, 4.5, 4.7, 4.3, 4.00, 4.2, 3.8, 4.9, 3.7, 4.6, 4.3, 3.5, 4.4, 4.4

Grade: 3.5, 3.2, 2.8, 3.3,

6 0

2 years ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X \geq 5)$

And we can use the complement rule:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

4 0

3 years ago