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Naily [24]
3 years ago
8

The lifeguard of the beach resort is on his post which is 4 m high. A boy in the pool is 9 meters away from him. Find the angle

of depression from the lifeguard to the boy.​
Mathematics
1 answer:
Dovator [93]3 years ago
8 0

\large \underline{ \mathbb{QUESTION:}}

The lifeguard of the beach resort is on his post which is 4 m high. A boy in the pool is 9 meters away from him. Find the angle of depression from the lifeguard to the boy.

\large\underline{ \mathbb{ANSWER  \: \& \: SOLUTION:}}

\large \tt{ tan \: x \:  =  \:  \frac{opposite}{adjacent} }

\large \tt{tan  \: x \:  =  \:  \frac{4}{9}}

\large \tt{ \:   \: \:  \:   \:  \:  \: \: x \:  =  \:  tan ^{ - 1}  \:  (0.444)}

\large \tt {\:  \:  \:  \:  \:  \:  \:  \: x \:  =  \: 23.96 ^{o} }

\:\:\:\:\:\:\:\: \large \boxed{\tt{\red{  x \:  =  \: 24 ^{o} }}}

Therefore the angle of depression from the lifeguard to the boy is 24°.

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Mice21 [21]

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We are given that the distance Rachel runs to her bus stop is 2km

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We get 45 + x = 4.5/(0.417 - y)

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(45y + 2)/y = 4.5(0.417-y)

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(45y + 2)(0.417 - y) = 4.5y

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Collecting like terms

-45y2 + 18.765y -2y - 4.5y + 0.834 = 0

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Then we put y = 0.331 in (1)

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x = 2/0.331

x = 6.042km/h

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